Its letter C. 5N to the left. Since Jeremy's force in Newtons are higher than Amanda's (in newtons), and since Jeremy's force directs to the left, then the direction of the force will be to the LEFT. Then subtract the higher one to the lower one so that would be: 10N-5N=5N. So it is C. 5N to the left.
Answer:
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Answer:
The correct option is B. an alpha particle.
Explanation:
When ²³Na is bombarded with protons
, ²⁰Ne and one alpha particle
is released.
The reaction is as follows:

Therefore, an alpha particle and ²⁰Ne are released when ²³Na is bombarded with protons.
E=hf
E=6.626e-34[Js]•1500e3[Hz]=9.939e-28[J]
For eV divide this by electron charge
9.939e-28[J]/1.6022e-19[C/e]=
6.203e-9eV
To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

Where,
= Mass of each object
= Initial Velocity of Each object
= Final Velocity
Our values are given as




Replacing we have that



Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s