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Stels [109]
3 years ago
9

Indirect economic value to Steven and his family,

Physics
2 answers:
Eduardwww [97]3 years ago
7 0

Answer:

indirect economic value

erastovalidia [21]3 years ago
7 0
My name is Kari how can I help you?
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A car is travelling with a velocity of 10 m/s and has a mass of 550 kg. The<br> car has<br> energy.
Elenna [48]

Answer: The car has a kinetic energy (because it's in motion) of:  27500J

Explanation:

Formula: E=\frac{1}{2}mv^2

E=\frac{1}{2}mv^2

E=\frac{1}{2}(550kg)(10m/s)^2

E=\frac{1}{2}(550kg)(100m^2/s^2)

E=\frac{1}{2}(55000J)\\E=27500J

3 0
3 years ago
Explain why fishes survive in ponds even when the temperature is below 0°c
zmey [24]

Answer:

After sufficient thickness of ice is formed it prevents further loss of heat from the bottom layers of water. This is why fishes and other aquatic animals and plants can survive in ponds and other water bodies even when the atmospheric temperature reaches or is well below 0 degrees.The anomalous expansion of water helps preserve aquatic life during very cold weather. When temperature falls, the top layer of water in a pond contracts becomes denser and sinks to the bottom. ... Thus, even though the upper layer are frozen, the water near the bottom is at 4°C and the fishes can survive in it easily.

3 0
3 years ago
5- A 2500g object is pushed with 55N for 12m in 11s, there was a force of friction of 30N.
Assoli18 [71]

Answer:

1kg =1000g

2.5kg

D=12m

t=11s

F=2.5KG

Explanation:

work done =f.d

=2.5×12

=30Nm

55-30

average speed

final - initial

divide by time t(s)

3 0
2 years ago
Determine the magnitude of the momentum of a ... 107-kg halfback moving eastward at 8 m/s.The halfback's momentum in kgm/s is:
Veronika [31]

Given:

The mass of the halfback is m = 107 kg

The speed of the halfback is v = 8 m/s

To find the momentum.

Explanation:

The momentum of the halfback is

\begin{gathered} p=\text{ mv} \\ =\text{ 107}\times8 \\ =\text{ 856 kg m/s} \end{gathered}

Thus, the momentum of the halfback is 856 kg m/s

3 0
1 year ago
In a certain process, the energy change of the system is 250 \rm kJ. The process involves 480 \rm kJ of work done by the system.
alisha [4.7K]

Answer:

\Delta Q=-230kJ

Explanation:

Using the first law of thermodynamics:

\Delta U=\Delta Q-W

Where \Delta U is the change in the internal energy of the system, in this case  \Delta U=250kJ, \Delta Q is the heat tranferred, and W is the work,  W=-480kJ with a negative sign since the work is done by the system.

From the previous equation we solve for heat, because it is the unknown variable in this problem

\Delta Q=\Delta U +W

And replacing the known values:

\Delta Q=250kJ +(-480kJ)

\Delta Q=250kJ -480kJ

\Delta Q=-230kJ

The negative sign shows us that the heat is tranferred from the system into the surroundings.

3 0
4 years ago
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