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vredina [299]
3 years ago
9

Where will the spacecraft be when the gravitational forces acting on it are equal?

Physics
1 answer:
klio [65]3 years ago
6 0
It would be not be able to move yet it would be in the air

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PLEASE HELPPP<br> answer choices are insulator and conductor
Sergeeva-Olga [200]
Conductor is the answer
6 0
3 years ago
Energy waves traveling at the speed of light are called _____.
koban [17]
RADIATION

There are three types of heat transfer or heat propagation; conduction, convection and radiation. Heat transfer is the process by which heat projects externally however, depending on the temperature and pressure. Also called the movement of heat from a low temperatured state which increases as heat progresses.
Conduction is the heat transfer by contact, immediate contact.
Convection is the transfer of heat through air and water.
<span>Radiation is the transfer of heat regardless of the presence of atoms or particles.<span>
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8 0
3 years ago
Read 2 more answers
n alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 5.94 cm in a uniform magnetic field with B = 1.10 T.
9966 [12]

Answer:

a). V = 3.13*10⁶ m/s

b). T = 1.19*10^-7s

c). K.E = 2.04*10⁵

d). V = 1.02*10⁵V

Explanation:

q = +2e

M = 4.0u

r = 5.94cm = 0.0594m

B = 1.10T

1u = 1.67 * 10^-27kg

M = 4.0 * 1.67*10^-27 = 6.68*10^-27kg

a). Centripetal force = magnetic force

Mv / r = qB

V = qBr / m

V = [(2 * 1.60*10^-19) * 1.10 * 0.0594] / 6.68*10^-27

V = 2.09088 * 10^-20 / 6.68 * 10^-27

V = 3.13*10⁶ m/s

b). Period of revolution.

T = 2Πr / v

T = (2*π*0.0594) / 3.13*10⁶

T = 1.19*10⁻⁷s

c). kinetic energy = ½mv²

K.E = ½ * 6.68*10^-27 * (3.13*10⁶)²

K.E = 3.27*10^-14J

1ev = 1.60*10^-19J

xeV = 3.27*10^-14J

X = 2.04*10⁵eV

K.E = 2.04*10⁵eV

d). K.E = qV

V = K / q

V = 2.04*10⁵ / (2eV).....2e-

V = 1.02*10⁵V

7 0
3 years ago
The given function represents the position of a particle traveling along a horizontal line. s(t) = 2t3 − 3t2 − 36t + 6 for t ≥ 0
igor_vitrenko [27]

1) The velocity of the particle is given by the derivative of the position. So, if we derive s(t), we get the velocity of the particle as a function of the time:

v(t)=s'(t)=(2t^3-3t^2-36t+6)'=6t^2-6t-36

2) The acceleration of the particle is given by the derivative of the velocity. So, if we derive v(t), we get the acceleration of the particle as a function of the time:

a(t)=v'(t)=(6t^2-6t-36)'=12t-6

8 0
3 years ago
In the image below, which objects would have a greater gravitational force between them, Objects A and B, or Objects B and C? Gi
Arada [10]
I don't see an image, but the force of gravity depends on mass and distance. If the mass and the distance are different, you divide (mass÷distance).the greater the number the greater the force of gravity.

Tell me if you need more info.
4 0
3 years ago
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