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vredina [299]
3 years ago
9

Where will the spacecraft be when the gravitational forces acting on it are equal?

Physics
1 answer:
klio [65]3 years ago
6 0
It would be not be able to move yet it would be in the air

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A tube with a cap on one end, but open at the other end, has a fundamental frequency of 130.8 Hz. The speed of sound is 343 m/s
sergey [27]

Answer:

Y = V / f      where Y equals wavelength

4 Y1 = V / f1       for a closed pipe the wavelength is 1/4 the length of the pipe

2 Y2 = V / f2   for the open pipe the wavelength is 1/2 the length of the pipe

Y1 / Y2 = 2 = f2 / f1      dividing equations

f2 = 2 f1  

the new fundamental frequency is 2 * 130.8 = 261.6

(The new wavelength is 1/2 the original wavelength so the frequency must double to produce the same speed.

8 0
2 years ago
Acceleration of gravity on jupiter
Viefleur [7K]

The acceleration of gravity on Jupiter is listed as  <em>24.79 m/s²</em> .

That's roughly  2.53  times its value on Earth.  So if you weigh, let's say,
130 pounds on Earth, then you would weigh about 328 pounds on Jupiter.



5 0
3 years ago
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Describe two examples of how humans use electromagnetic waves.
Alex73 [517]
Electromagnetic waves are used in everyday life. You are looking at your computer screen right now. The light that is coming off of the screen is visible light, a form of electromagnetic radiation. Electromagnetic waves are also used to send information. For example, AM or FM radios are radio waves that transfer sound information to your local radio.
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3 years ago
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When you stand with the wind blowing on your back, the low pressure center is
yan [13]
✷ Question: <span>When you stand with the wind blowing on your back, the low pressure center is _____. 

Answer: Letter A

</span><span>✐ </span><span>Explanation: When wind hits your back, all the molecules are in front of you.

</span>Hope that helps! ★ If you have further questions or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia
5 0
2 years ago
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Which is the destructive interference formula for diffraction grating problems? dsin = dcos = dcos = n dsin = n.
shusha [124]

The destructive interference formula for diffraction grating problems is d sin \theta = (n+\frac{1}{2})\lambda.

<h3>What is the definition of destructive interference?</h3>

Destructive interference happens when the maxima of two waves are 180° out of phase a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.

The formula for brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:

\rm d sin \theta = n \lambda

The grating spacing is denoted by d, the angle of light is denoted by a the fringe order is denoted by n, and the wavelength is denoted by \rm \lambda.

The destructive interference formula is now based on the fact that destructive interference occurs between the fringes.

Hence the destructive interference formula for diffraction grating problems is d sin \theta = (n+\frac{1}{2})\lambda.

To learn more about destructive interference refer to the link;

brainly.com/question/16098226

5 0
2 years ago
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