Y ^(-2/3)^-6 = y^12/3 = y^4
x^(1/2)^ -6 = x^-3 = 1 x^3
so the answer is y^4 * 1 /x^3 = y^4 / x^3
A
Answer:
A
Step-by-step explanation:
Answer:
Formula: (x^2 -h) +(y^2 -k)=r^2
The number on the right side of the = is the radius of the circle squared.
(h,k) is the center of the circle.
Answer:
see explanation
Step-by-step explanation:
Inequalities of the type | x | ≤ a always have solutions of the form
- a ≤ x ≤ a
Given
| x - 1 | ≤ 1 then
- 1 ≤ x - 1 ≤ 1 ( add 1 to each of the 3 intervals )
0 ≤ x ≤ 2
Since we require an integer solution then x = 0, 1, 2
Quotient is the result of a division.
1 - 1/x
