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DedPeter [7]
3 years ago
5

Rob says that this graph shows a proportional relationship. Is he correct? Explain.

Mathematics
3 answers:
Blizzard [7]3 years ago
8 0

Answer:

No. Rob was correct to extend the lines to the origin, but the points should be on a single straight line. He made two straight lines.

Step-by-step explanation:

Hope this helps

zysi [14]3 years ago
5 0

Answer:

No. Rob was correct to extend the lines to the origin, but the points should be on a single straight line. He made two straight lines.

Step-by-step explanation:

this is from the sample responds so you can see what they want

Lina_smartkid2 years ago
0 0

No. Rob was correct to extend the lines to the origin, but the points should be on a single straight line. He made two straight lines.

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/3299236-rob-says-that-this-graph-shows-a-proportionalbrrelationship-is.html

I did the test!!!

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a drink recipe calls for lemon juice and apple juice. the equation below represents the proportional relationship between the cu
GREYUIT [131]

Answer: ima newbie

Step-by-step explanation:

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8 0
2 years ago
<img src="https://tex.z-dn.net/?f=8x%20%2B%204%20%3D%205x%20-%2011%20" id="TexFormula1" title="8x + 4 = 5x - 11 " alt="8x + 4 =
Anon25 [30]
8x + 4 = 5x - 11

Subtract 5x from both sides:
3x + 4 = -11

Subtract 4 from both sides:
3x = -15

Divide both sides by 3:
x = -5

Answer : x = -5
7 0
3 years ago
Help plzz division math prob
leva [86]

g(x) = x - 3 = 0

g(x) = x = 3

f(x) = 2x^3 + x - 4

f(3) = 2(3)^3 + 3 - 4

f(3) = 2(27) - 1

f(3) = 54 - 1

f(3) = 53

The remainder when f(x) is divided by x - 3 is <u>53</u>.

3 0
2 years ago
Please solve <br> 5/5 ÷ 1/2 =
Gala2k [10]
<span>5/5 ÷ 1/2 =
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5 0
3 years ago
Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer
QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

7 0
2 years ago
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