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Debora [2.8K]
3 years ago
7

What decimal is equivalent to 6/8 (six-eighths)? * 20 points 6.8 0.68 7.5 0.75

Mathematics
2 answers:
Elza [17]3 years ago
8 0

Answer:

0.75 :)

Step-by-step explanation:

sergejj [24]3 years ago
3 0
The answer to this question is 0.75
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Pls help me asap tyyyyyyy
GenaCL600 [577]

Answer:

the answer is A

Step-by-step explanation:

she put that 1.8 is equal to 18% but 0.18 is, therefore its A.

8 0
3 years ago
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A student answers 160 of 200 questions on an exam correctly. What percent of the questions did he answer correctly?
Alexandra [31]

Dive correct answers by total questions:

160/200 = 0.80

Multiply by 100 to get percent:

0.80 x 100 = 80%

5 0
3 years ago
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Find the least common denominators of these two rational experssions -1/y and 2/5y
algol13
The least common denominator is 5y, and can be obtained by multiplying 
-1/y by 5/5 to get -5/5y. 

If we add the numbers using the least common denominator, we get:
-5/5y + 2/5y = -3/5y
6 0
3 years ago
Please help I got stuck on this on thank you
svetlana [45]
Answer is B. 3

2/3 x 3  = 6/3 = 2 cups
7 0
3 years ago
6.Suppose the Gallup Organization wants to estimate the population proportion of those who think there should be a law that woul
drek231 [11]

Answer:

A sample of n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2 is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.

This means that n = 1012, \pi = \frac{374}{1012} = 0.3696

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

How large a sample size is needed to be 95% confident with a margin of error of E?

A sample size of n is needed, and n is found when M = E.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

E = 1.96\sqrt{\frac{0.3696*0.6304}{n}}

E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}

\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2

n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2

A sample of n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2 is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

4 0
3 years ago
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