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Triss [41]
4 years ago
5

Calculate the change in enthalpy for Reaction 2.

Chemistry
2 answers:
seropon [69]4 years ago
7 0
 Best Answer:<span>  </span><span>Sorry its kind of hard to explain, you just need to study hesslaw, practice makes perfect, keep studying! 
A. REACTION 2 IS MULTIPLIED BY 3 (HESS LAW) 
ΔH2= -6129 j 
B. IF REACTION IS REVERSED YOU FLIP THE SIGN OF ΔH 
ΔH = 92.3 kJ 
C. KIND OF HARD TO EXPLAIN, BUT I CAN TRY AND SHOW YOU 
EQUATION 1 (FLIP) CH4 --> C + H2 
EQUATION 4 (FLIP AND MULTIPLY BY 2) H2O(g) --> H2O(l) 
ΔH = -890.7</span>
Oduvanchick [21]4 years ago
3 0

[3 mol CO2(g) + 4 mol H2O(g)] - [1 mol C3H8(g) + 5 mol O2(g)]

[3 · (213.74 J/mol·K) + 4 · (188.825 J/mol·K)] - [1 · (269.9 J/mol·K) + 5 · (205.138 J/mol·K)]

=100.93 J/mol·K

Answer: 100.93 J/mol·K

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