Someone help me please please someone help me please

Chemistry

1 answer:

Dmitry_Shevchenko [17]4 years ago

5 0

It's just graphing. puck acceleration is the x axis and swing length is the y axis

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What mass of al is required to completely react with 25.0 grams of mno2?

horsena [70]

Mass of MnO2 = 25 g
The reaction would be 3MnO2 + 4Al --> 3Mn(s) + 2Al2O3
Molar mass of Al = 26.982 g/mol
Molar mass of MnO2 = 54.938 + 2(15.999) = 86.936 g/mol
Calculating the moles = 25 / 86.936 = 0.2876 mol.
Mole ratio MnO2 and Al considering the equation = 3 mol of MnO : 4 mol of Al
Calculating the moles of Al = 0.2876 mol MnO2 x (4 mol of Al / 3 mol of MnO)
Number of moles of Al = 0.3834
Getting the mass in grams as asked = 0.3834 mol x 26.982 g/mol = 10.34 grams.

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If 25 g of NH3, and 96 g of H2S react according to the following reaction, what is the

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<u>Explanation:</u>