Answer:
Mass of carbon dioxide = 7.48 g
Explanation:
Given data:
Mass of lithium carbonate = 12.5 g
Mass of carbon dioxide produced = ?
Solution:
Chemical equation:
Li₂CO₃ → Li₂O + CO₂
Number of moles of Li₂CO₃:
Number of moles = mass/ molar mass
Number of moles = 12.5 g /73.89 g/mol
Number of moles = 0.17 mol
Now we will compare the moles of Li₂CO₃ with CO₂.
Li₂CO₃ : CO₂
1 : 1
0.17 : 0.17
Mass of carbon dioxide:
Mass of carbon dioxide = number of moles × molar mass
Mass of carbon dioxide = 0.17 mol × 44 g/mol
Mass of carbon dioxide = 7.48 g
<u>Answer:</u> 1.2 moles of carbon dioxide is produced for the given value of oxygen.
<u>Explanation:</u>
The chemical reaction for the combustion of acetylene follows the equation:

By stoichiometry of the reaction:
5 moles of oxygen produces 4 moles of carbon dioxide.
So, 1.5 moles of oxygen will produce =
of carbon dioxide.
Hence, 1.2 moles of carbon dioxide is produced for the given value of oxygen.
Answer:
Mass = 88.12 g
Explanation:
Given data:
Mass of iron oxide = 126 g
Mass of iron formed = ?
Solution:
Chemical equation:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Number of moles of iron oxide:
Number of moles = mass/molar mass
Number of moles = 126 g/ 159.69 g/mol
Number of moles = 0.789 mol
Now we will compare the moles of iron with iron oxide.
Fe₂O₃ : Fe
1 : 2
0.789 : 2/1×0.789 = 1.578 mol
Mass of iron:
Mass = number of moles ×molar mass
Mass = 1.578 mol × 55.84 g/mol
Mass = 88.12 g
<span>Total mass of reactants is equal to the mass of products.</span>
The answer would be
A) synthesis