The vertex form of a quadratic function is:
f(x) = a(x - h)² + k
The coordinate (h, k) represents a parabola's vertex.
In order to convert a quadratic function in standard form to the vertex form, we can complete the square.
y = 2x² - 5x + 13
Move the constant, 13, to the other side of the equation by subtracting it from both sides of the equation.
y - 13 = 2x² - 5x
Factor out 2 on the right side of the equation.
y - 13 = 2(x² - 2.5x)
Add (b/2)² to both sides of the equation, but remember that since we factored 2 out on the right side of the equation we have to multiply (b/2)² by 2 again on the left side.
y - 13 + 2(2.5/2)² = 2(x² - 2.5x + (2.5/2)²)
y - 13 + 3.125 = 2(x² - 2.5x + 1.5625)
Add the constants on the left and factor the expression on the right to a perfect square.
y - 9.875 = 2(x - 1.25)²
Now, we need y to be by itself again so add 9.875 back to both sides of the equation to move it back to the right side.
y = 2(x - 1.25)² + 9.875
Vertex: (1.25, 9.875)
Solution: y = 2(x - 1.25)² + 9.875
Or if you prefer fractions
y = 2(x - 5/4)² + 79/8
Answer:
See attached sheet
Step-by-step explanation:
Percentage is out of a 100. Therefore, 35/100
Simplify 35/100
Becomes 7/20
Fraction of 35% is 7/20
Answer:
7 and 6 respectively
Step-by-step explanation:
Firstly, we have to solve the equations simultaneously.
2x + 7p = 56
3x - 11p = -45
Multiply equation I by 3 and ii by 2
6x +21p = 168
6x - 22p = -90
Subtract the second from first to yield:
43p = 258
p = 6
Insert this in equation 1 where we have 2x + 7p = 56
2x + 7(6) =56
2x + 42 = 56
2x = 14 and x = 7
The equilibrium price is 6 and the equilibrium quantity is 7
Part 1:
Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.
Thus, half the angle formed by the chord at the centre of the circle is given by:

Now,

Therefore, the radius of the circle is
10.4 cm to 1 d.p.
Part 2I:
Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

Now,

Part 2II:
Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately
12.9 cm.