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Nonamiya [84]
3 years ago
11

Find the value of x plsss

Mathematics
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

x=10.8

Step-by-step explanation:

9²+6²=c²

81+36=c²

117=c²

√117=10.81

x=10.81

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How do I factor this problem
Keith_Richards [23]

Answer:

−(3x−2)(7x+4)

Step-by-step explanation:

4 0
3 years ago
The probability of rolling a number less than 3 on a number cube 2/6. Jennifer rolls a number cube 60 times how many times shoul
Savatey [412]

Answer:

20 times

Step-by-step explanation:

Given the following :

Probability of rolling a number less than 3 on a number cube:

Required outcome = (1, 2)

Total possible outcomes = (1, 2, 3, 4, 5, 6)

Required outcome / Total possible outcomes

= 2 /6

= 1/3

Hence, if number cube is rolled 60 times, number of times a number less than 3 is expected :

(Probability of obtaining a number less than 3 in one roll × number of rolls)

= (1 / 3) × 60

= 60 / 3

= 20 times

5 0
3 years ago
Find the domain and range
tresset_1 [31]
Domain: all real numbers
Range: y>-3
4 0
2 years ago
Help with this question please!
Anton [14]

∠1 and ∠2 are alternate exterior angles where transversal BE crosses parallel lines AC and DF, therefore they are equal. ∠2 and ∠3 are opposite angles of a parallelogram, therefore they are equal.

... ∠1 = ∠2

... 3x -5 = 2x +15 . . . . substitute the given values

... x = 20 . . . . . . . . . . . add 5-2x

The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.

5 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

     -6 + (3*t) =  7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

         (6.8*t) = 13.4

                  t = 13.4/6.8

                  t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0
3 years ago
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