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a_sh-v [17]
3 years ago
13

Suppose that you decide to participate in a charity walkathon to raise money for your cause. Some people decide to donate a fixe

d amount, while others agree to donate a little money for every mile you walk. Before the event starts, you raised $25, and you have been pledged $1.50 for each mile you walk. The function defined by d(m)=1.5m+25 can be used to relate the miles you walk, m, and the amount of money donated to you in dollars, d(m).
Evaluate d(3).
Mathematics
1 answer:
natta225 [31]3 years ago
6 0

Answer:

Step-by-step explanation:

d(3)=1.5x3+25=29.5

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In a class with 28 students, there are 19 boys. What is the ratio of girls to boys? 9:19 19:28 19:9 28:9​
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The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by
Vikentia [17]

The answer will be t = sin((m.\frac{\pi}{6})+55) average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\

suppose x = m.\frac{\pi}{6}+55 and \frac{\pi}{2} = 90 degree

We know, cos(x+90°) = - sin(X)

⇒ cos((m.\frac{\pi}{6})+55+90degree)degree = -sin((m.\frac{\pi}{6})+55)

⇒ t = sin((m.\frac{\pi}{6})+55)

Hence the answer will be t = sin((m.\frac{\pi}{6})+55) average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

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brainly.com/question/27441712

#SPJ4

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