Answer:
The correct answer is 9:50.
Step-by-step explanation:
9:05+0:45=9:50
Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
Let's solve your equation step-by-step.
−2(4k−7)=22−8k
Step 1: Simplify both sides of the equation.
−2(4k−7)=22−8k
(−2)(4k)+(−2)(−7)=22+−8k(Distribute)
−8k+14=22+−8k
−8k+14=−8k+22
Step 2: Add 8k to both sides.
−8k+14+8k=−8k+22+8k
14=22
Step 3: Subtract 14 from both sides.
14−14=22−14
0=8
So, the answer is 0=8.
If you add them together you will get 11g
Answer:
The sign would be 784 ft. long.
Step-by-step explanation:
The sign would be painted across the total perimeter of the building.
- the distance across the front of the store is 294 feet
- the distance from the front to the back is one third of this distance = (1/3) × 294 = 98 ft.
The perimeter of a rectangular = 2(L + B)
L = length of the building = 294 ft.
B = Breadth of the building = 98 ft.
Perimeter of the chocolate factory that the Sign would be painted across = 2(294 + 98) = 784 ft.
Hope this Helps!!!
