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larisa86 [58]
2 years ago
10

A line includes the points (1, 6) and (10, 4). What is its equation in point-slope form? Use one of the specified points in your

equation. Write your answer using integers, proper fractions, and improper fractions in simplest form.
Mathematics
1 answer:
Kaylis [27]2 years ago
6 0
Y2-y1/x2-x1
4-6/10-1
-2/9 is the slope

y-y1=m(x-x1)
y-6=-2/9(x-1)
y-6=-2/9x-2/9
Multiply both sides by 9
9y-54=-2x-2
2x+9y=52

Therefore 2x+9y=52 is the equation
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Please help me out if you can!
Mkey [24]

Ok so we know that consecutive angles are supplementary and the diagonals bisect the angels so

2x-15+3x=90

5x=105

X=21

7 0
2 years ago
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Please help in question 3 please
Goryan [66]

Answer:

Step-by-step explanation:  84 kg is the correct Answer you are looking for.

8 0
3 years ago
What is the slope of a line that goes through the points (1, -5) and (-3, 2)?
Gnom [1K]
Use the slope formula
y sub 2-y sub 1. all over
x sub 2-x sub 1.
so
2+5
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5 0
3 years ago
Which best describes the orthocenter of a triangle?
Stolb23 [73]

Answer:

its A

Step-by-step explanation:

Its a because its A =)

7 0
1 year ago
Find the orthocenter of △ABC. A(2, 3), B(−4, −3), C(2, −3)
weqwewe [10]
ANSWER

\boxed { A. \: \: (2,-3) }

EXPLANATION.

The orthocenter is the point of intersection of any two altitudes of the triangle.

First, you need to determine the slope of each side of the triangle.

△ABC has vertices A(2, 3), B(−4, −3), C(2, −3).

slope \: of \: AB = \frac{3 - - 3}{2 - - 4} = \frac{6}{6} = 1

slope \: of \: AC = \frac{ 3 - - 3}{2 - 2} = \frac{6}{0}

This line has undefined slope, which means it is a vertical line.

slope \: of \: BC = \frac{ - 3 - - 3}{ 2 - - 4} = \frac{0}{6} = 0

The slope of this line is zero, meaning the line is a horizontal line.

This implies that side BC and side AC of the given triangle are perpendicular and will intersect at C since they are the altitudes of triangle ABC.

Hence the orthocentre is

(2,-3)

See diagram in attachment.

5 0
2 years ago
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