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mars1129 [50]
4 years ago
13

Some more of my cousin work and im putting more up

Physics
1 answer:
Dovator [93]4 years ago
6 0

Answer:

Proper nouns

hope this helps =3

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What is dispersion, and how is it related to diffraction and refraction?
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Explain how bats use ultrasound to catch a prey​
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A fire hose held near the ground shoots water at a speed of 6.8 m/s. At what angle(s) should the nozzle point in order that the
Vesna [10]

So, based on the angle values that have been found, the angle of elevation of the nozzle can be <u>16° or 74°</u>.

<h3>Introduction</h3>

Hi ! This question can be solved using the principle of parabolic motion. Remember ! When the object is moving parabolic, the object has two points, namely the highest point (where the resultant velocity is 0 m/s in a very short time) and the farthest point (has the resultant velocity equal to the initial velocity). At the farthest distance, the object will move with the following equation :

\boxed{\sf{\bold{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}}}

With the following condition :

  • \sf{x_{max}} = the farthest distance of the parabolic movement (m)
  • \sf{v_0} = initial speed (m/s)
  • \sf{\theta} = elevation angle (°)
  • g = acceleration due to gravity (m/s²)

<h3>Problem Solving :</h3>

We know that :

  • \sf{x_{max}} = the farthest distance of the parabolic movement = 2.5 m
  • \sf{v_0} = initial speed = 6.8 m/s
  • g = acceleration due to gravity = 9.8 m/s²
<h3>What was asked :</h3>
  • \sf{\theta} = elevation angle = ... °

Step by Step :

  • Find the equation value \sf{\bold{theta}} (elevation angle)

\sf{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}

\sf{x_{max}  \cdot g = (v_0)^2 \cdot \sin(2 \theta)}

\sf{\frac{x_{max}  \cdot g}{(v_0)^2} =   \sin(2 \theta)}

\sf{\frac{2.5  \cdot 9.8}{(6.8)^2} =   \sin(2 \theta)}

\sf{\frac{2.5  \cdot 9.8}{(6.8)^2} =  \sin(2 \theta)}

\sf{\frac{24.5}{46.24} = \sin(2 \theta)}

\sf{\sin(2 \theta) \approx 0.53}

\sf{\cancel{\sin}(2 \theta) \approx \cancel{\sin}(32^o)}

  • Find the angle value of the equation by using trigonometric equations. Provided that the parabolic motion has an angle of elevation 0° ≤ x ≤ 90°.

First Probability

\sf{2 \theta = 32^o + k \cdot 360^o}

\sf{\theta = 16^o + k \cdot 180^o}

→ \sf{k = 0 \rightarrow 16^o + 0 = 16^o} (T)

→ \sf{k = 1 \rightarrow 16^o + 180^o = 196^o} (F)

Second Probability

\sf{2 \theta = (180^o - 32^o) + k \cdot 360^o}

\sf{2 \theta = 148^o + k \cdot 360^o}

\sf{\theta = 74^o + k \cdot 180^o}

→ \sf{k = 0 \rightarrow 74^o + 0 = 74^o} (T)

→ \sf{k = 1 \rightarrow 74^o + 180^o = 254^o} (F)

\boxed{\sf{\therefore \theta \{16^o , 74^o\} }}

<h3>Conclusion</h3>

So, based on the angle values that have been found, the angle of elevation of the nozzle can be 16° or 74°.

8 0
3 years ago
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