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3 years ago

Is a nucleus that absorbs at 4.13 δ more shielded or less shielded than a nucleus that absorbs at 11.45 δ?

Physics

1 answer:

NeTakaya3 years ago

3 0

Explanation:

A nucleus that absorbs 11.45δ is less shielded than a nucleus that absorbs at 4.13δ.

the nucleus that absorbs at 11.45δ requires weaker applied field strength to come into resonance than the nucleus that absorbs at 4.13δ.

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A constant net force acts on an object. which of the following best describes the object's motion?

Anton [14]

The object is moving with a decreasing acceleration. The object is moving with a constant velocity.

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4 years ago

A straight wire carries a 12-A current eastward and a second straight wire carries a 14-A current westward. The wires are separa

USPshnik [31]

Answer:

$5.12\cdot 10^{-4} N$

Explanation:

The force exerted between two current-carrying wires is given by

$F=\frac{\mu_0 I_1 I_2 L}{2 \pi r}$

where

$\mu_0$ is the vacuum permeability

I1 and I2 are the two currents

L is the length of the segment of wire on which we want to calculate the force

r is the distance between the wires

In this problem we have:

$I_1 = 12 A\\I_2 = 14 A\\r = 42 cm = 0.42 m\\L = 6.4 m$

Substituting into the formula, we find:

$F=\frac{(4\pi \cdot 10^{-7})(12)(14)(6.4)}{2 \pi (0.42)}=5.12\cdot 10^{-4} N$

And since the direction of the two currents is opposite, the force between the wires is repulsive.

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4 years ago

As a space shuttle moves through the dilute ionized gas of Earth's ionosphere, the shuttle's potential is typically changed by -

zvonat [6]

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3 years ago

A child and sled with a combined mass of 58.0 kg slide down a frictionless slope. If the sled starts from rest and has a speed o

erma4kov [3.2K]

Answer:

The height is $h = 0.5224 \ m$

Explanation:

From the question we are told that

The combined mass of the child and the sled is $m = 58.0 \ kg$

The speed of the sled is $u = 3.20 \ m/s$

Generally applying SOHCAHTOA on the slope which the combined mass is down from

Here the length of the slope(L) where the combined mass slides through is the hypotenuses

while the height(h) of the height of the slope is the opposite

Hence from SOHCAHTOA

$sin (\theta) = \frac{h}{L}$

=> $Lsin(\theta) = h$

Generally from the kinematic equation we have that

$v^2 = u^2 + 2aL$

Here the u is the initial velocity of the combined mass which is zero since it started from rest

and a is the acceleration of the combined mass which is mathematically evaluated as

$a = g * sin (\theta )$

$v^2 = u^2 + 2 * g * sin (\theta )L$

=> $2Lsin(\theta ) = \frac{v^2 - u^2 }{g}$

=> $h = \frac{ v^2 - u^2}{2g}$

=> $h = \frac{ 3.20^2 - 0^2}{2 * 9.8 }$

=> $h = 0.5224 \ m$

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3 years ago

A 2.0-m wire carrying a current of 0.60 A is oriented parallel to a uniform magnetic field of 0.50 T. What is the magnitude of t

konstantin123 [22]

Answer:

The force experienced is 0.6 N

Explanation:

Given data

length of wire L= 2 m

current in wire I= 0.6 A

magnetic field B= 0.5

The force experienced can be represented as

$F= BIL$

$F= 0.5*0.6*2\\\F= 0.6 N$

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3 years ago