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lawyer [7]
3 years ago
15

What is dispersion, and how is it related to diffraction and refraction?

Physics
1 answer:
iragen [17]3 years ago
8 0
Refraction is simply the bending of light when it moves from one material into another. If light is beamed at 90° to a surface, no bending happens. But if you shine the light at an angle it will bend one way or another.
   
    Diffraction is a process in which a beam of light travels through a gap or around a barrier, and spreads out as a result.

<span>   Dispersion is the property that the speed of light in a transparent material is different for different wavelengths. Thus the index of refraction is likewise different.</span>
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Mrs. Martin’s drive to school is 25 miles from her house. It takes her half an hour to get there. The speed limit is 40 mph. Was
oee [108]

Answer:

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7 0
3 years ago
A 100 kg mass is pulled along a frictionless surface by a horizontal force F such that its acceleration is 8.0 m/s2. A 20 kg mas
nadya68 [22]

Answer:

a) 60 N

b) 860 N

Explanation:

Given that,

m_1 = 100 kg

m_2 = 20 kg

a_{1} = 8.0 \frac{m}{s^{2}}

a_{2} = 3.0 \frac{m}{s^{2}}

a) By Newton's Law,

∑F_{m_2,x} = f_k = m_{2} * a_{2}

∑F_{m_2,y} = F_{N} - m_{2} * g = 0

Hence,

f_k = m_2 * a_2 = 20 * 3 = 60 N

b) By Newton's Law

∑F_{m_1,x} = F = m_{1} * a_{1}

Hence,

F = m_{1} * a_{1} = 100 * 8 = 800 N

Net force acting on 100 kg mass,

F_{net} = F + f_k = 800 + 60 = 860 N

6 0
3 years ago
A student sits at rest on a piano stool that can rotate without friction. The moment of inertia of the student-stool system is 4
bija089 [108]

Answer:

   w = 0.55 rad / s

Explanation:

For this exercise let's use the conservation of angular momentum, let's write the moment in two moments

Initial

    L₀ = r p + 0

    L₀ = r mv

The first term is the angular momentum of the mass

Final

      Lf = (I + m r²) w

Where I is the moment of inertia of the stool and the other term is the moment of inertia of the mass

      L₀ = Lf

      r mv = (I + m r²) w

      w = m r v / (I + m r²)

Let's calculate

      w = 2.0 0.45 3.0 / (4.5 + 2.0 0.45²)

      w = 2.7 / 4.9

     w = 0.55 rad / s

4 0
4 years ago
A wire carrying a current is shaped in the form of a circular loop of radius 3.0mm If the magnetic field strength that this curr
ahrayia [7]

Answer:

Current, I = 5.3 A

Explanation:

It is given that,

Radius of circular loop, r = 3 mm = 0.003 m

Magnetic field strength, B = 1.1 mT = 0.0011 T

We need to find the magnitude of the current that flows through the wire. The magnetic field for a current carrying wire is given by :

B=\dfrac{\mu_o I}{2r}

I=\dfrac{2Br}{\mu_o}

I=\dfrac{2\times 0.0011\ T\times 0.003\ m}{4\pi\times 10^{-7}}

I = 5.25 A

or

I = 5.3 A

So, the magnitude of the current that flows through the wire is 5.3 A. Hence, this is the required solution.

8 0
4 years ago
Using software, a simulation of a javelin being thrown both on Earth and on the moon is created. In both cases, the velocity and
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Since the gravity at the moon is around 6 times weaker, we have that the downwards pull is around 6 times smaller. In equations, we have that g of the moon=g of Earth/6 and since the weight is F=m*g, the force is 1/6th of the force on earth. Hence, the distance is going to be around 6 times larger than the distance traversed on Earth and thus the correct relation is A=6y.
6 0
4 years ago
Read 2 more answers
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