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jek_recluse [69]
3 years ago
15

Explain how bats use ultrasound to catch a prey​

Physics
1 answer:
Gnoma [55]3 years ago
8 0

Answer:

Ultrasound is used by bats to navigate (move) and catch prey. Ultrasonic squeaks are produced by bats. These squeaks ponder prey and then return to the bat's ear. This provides bats with information about the location of prey, allowing them to catch it.

Explanation:

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When the pivot point of a balance is not at the center of mass of the balance, how is the net torque on the balance calculated?
viktelen [127]

Answer:

Explanation:

Net torque is calculated by multiplying the force with distance from the point of application of force to the point of pivot .

If more than 2 forces are present, then we either subtract the product of forces with their respective distances from pivot point or we add them . It depends on whether they both are present on opposite sides of pivot or on same side of pivot .

When a force is applied directly to the pivot point of balance, then the torque on due that force = 0 (zero) .

It is so because the torque is defined as the product of force and perpendicular distance from the pivot point but here the distance is 0 , therefore torque is zero.

8 0
4 years ago
NEED HELP WITH PHYSICS HW! HURRY!! (**need expert**)
Slav-nsk [51]

Cable cd or dvd??.

Explanation:

Hope you answer fast

4 0
3 years ago
Read 2 more answers
What is the impact force on a 0.5 kg object if it falls 3 meters and hits a carpeted floor at 8 m/s, stopping in 0.10 seconds?
Cerrena [4.2K]

the I'm pact force of 0.5 is lol u guys go and study why r u asking answers

4 0
3 years ago
Móvil A : V = 16 m/s ; t = 5 sMóvil B : V = 15 m/s ; t = 6 s Móvil C : V = 24 m/s ; t = 3 s Calcular la distancia que recorre ca
patriot [66]

Answer:

dC = 72m < dA = 80m < dB = 90m

Explanation:

In order to calculate the distance traveled by each mobile, you use the following formula:

d=vt          (1)

d: distance traveled

v: speed of the car

t: time of the motion

You replace the values of v and t for each mobile:

mobile A:

d_A=v_At_A=(16m/s)(5s)=80m

mobile B:

d_B=v_Bt_B=(15m/s)(6s)=90m

mobile C:

d_C=v_Ct_C=(24m/s)(3s)=72m

Then, you obtain that he distances traveled by the mobiles show:

dC = 72m < dA = 80m < dB = 90m

4 0
3 years ago
Approximately 80% of the energy used by the body must be dissipated thermally. The mechanisms available to eliminate this energy
Semenov [28]

Answer:

the correct answer is c) 23 g

Explanation:

The heat lost by the runner has two parts: the heat absorbed by sweat in evaporation and the heat given off by the body

     Q_lost = - Q_absorbed

     

The latent heat is

      Q_absorbed = m L

The heat given by the body

      Q_lost = M c_{e} ΔT

       

where m is the mass of sweat and M is the mass of the body

       m L = M c_{e} ΔT

        m = M c_{e} ΔT / L

let's replace

        m = 90  3.500  1.8 / 2.42 10⁶

 

        m = 0.2343 kg

reduced to grams

        m = 0.2342 kg (1000g / 1kg)

        m = 23.42 g

 the correct answer is c) 23 g

8 0
3 years ago
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