Ask question

Ask question

All categories

3 years ago

8

1+2g=-7 how do you do this?

2 answers:

blsea [12.9K]3 years ago

8 0

Answer:

you would - 1 to -7 and get -8 then divide -8 by -2 than it would be 4

Step-by-step explanation:

s2008m [1.1K]3 years ago

7 0

I like my equations to have the variable before the constant.

2g+1=-7

Subtract 1 from the left side. Remember, whatever you do on one side, you MUST do it on the other.

2g=-8

Divide 2 from BOTH sides.

g=-4

Hope this helps!

:)

You might be interested in

If a person rows to this favorite fishing spot 17 miles downstream in the same amount of the time he rows 1 mile upstream and if

makvit [3.9K]

We use the formula : Displacement = Average Velocity * Time ;
17 = ( v + 8 ) * t ;
1 = ( v - 8 ) * t ;
where v = the velocity of the boat; t is the time from expression " ... in the same amount of the time he rows ....."

Then 17 / 1 = (v + 8) / ( v - 8 ) ;
v + 8 = 17( v - 8 );
v + 8 = 17v - 136 ;
144 = 16v ;
v = 144 / 16;
v = 9 mph ;

18 = 9 * x ;
x = 18 / 9 ;
x = 2 hours ;

The answer is 2 hours ;

4 0

3 years ago

The cost of 6one by two metere

Alik [6]

Answer:

Rs 17 3/4

Step-by-step explanation:

Cost of 6 1/2 m = 115 3/8

Cost of 1 m = x

x = 115 3/8 ÷ 6 1/2
x = (115*8 +3)/8 ÷ 13/2
x = 923/8 × 2/13
x = 923/(4*13)
x = 923/52
x = 17 39/52
x = 17 3/4

Cost of 1 meter is Rs 17 3/4

5 0

3 years ago

Who likes the oc i made for me its just one of the many sides I have

Mamont248 [21]

yes its amazing keep doing these<3

3 0

3 years ago

Envelopes are sold in packages of 40. There are 4 large envelopes in each package. How many la

topjm [15]

Answer:

You will get 16 Large envelopes

7 0

3 years ago

The dimensions of a rectangle are √50a^3b^2 and √200a^3. What is the students error?

bearhunter [10]

Answer:

The student incorrectly simplified $30ab\sqrt{2a}+20a\sqrt{2a}$ .

Thus, option D is correct.

<u></u>

Step-by-step explanation:

The formula to determine the Perimeter of a rectangle of width w and length l is expressed as:

$P = 2l + 2w$

In other words, the perimeter can be determined by multiplying the length and width by 2 and adding the result.

In our case, the dimensions of a rectangle are $\sqrt{50a^3b^2}$ and $\sqrt{200a^3}\:\:$ .

Here is the student's solution:

$2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}$

$=10ab\sqrt{2a}+20a\sqrt{2a}$

$=30ab\sqrt{2a}$

The student made an error in calculating $30ab\sqrt{2a}+20a\sqrt{2a}$ , because $30ab\sqrt{2a}+20a\sqrt{2a}$ are not like terms.

Hence, $30ab\sqrt{2a}+20a\sqrt{2a}$ can not be simplified to $30ab\sqrt{2a}$

Therefore, the student incorrectly simplified $30ab\sqrt{2a}+20a\sqrt{2a}$ .

Thus, option D is correct.

<u></u>

<u></u>

<u>Here is the correct Solution:</u>

$2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}$

$=10ab\sqrt{2a}+20a\sqrt{2a}$

7 0

3 years ago

Read 2 more answers