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statuscvo [17]
2 years ago
8

1+2g=-7 how do you do this?

Mathematics
2 answers:
blsea [12.9K]2 years ago
8 0

Answer:

you would - 1 to -7 and get -8 then divide -8 by -2 than it would be 4


Step-by-step explanation:


s2008m [1.1K]2 years ago
7 0

I like my equations to have the variable before the constant.

2g+1=-7

Subtract 1 from the left side. Remember, whatever you do on one side, you MUST do it on the other.

2g=-8

Divide 2 from BOTH sides.

g=-4

Hope this helps!

:)

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Answer:

The equation of the ellipse is \frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1

Step-by-step explanation:

The standard form of the equation of an ellipse with center (0 , 0) is

\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 , where

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- The coordinates of the foci are (± c , 0)

∴ c = ±8

∵ It has Vertices at (± 17 , 0)

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∵ c² = a² - b²

- Substitute the values of c and a to find b

∴ (8)² = (17)² - b²

∴ 64 = 289 - b²

- Add b² to both sides

∴ b² + 64 = 289

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∵ The equation of the ellipse is \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

- Substitute the values of a and b in it

∴ \frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1 ⇒ \frac{x^{2}}{289}+\frac{y^{2}}{225}=1  

∴ The equation of the ellipse is \frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1

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