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seropon [69]
3 years ago
12

Ammonium phosphate is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid with

liquid ammonia. Calculate the moles of ammonia needed to produce 0.060 mol of ammonium phosphate. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
Chemistry
1 answer:
ankoles [38]3 years ago
8 0

Answer:

n_{NH_3}=0.18molNH_3

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

H_3PO_4(aq)+3NH_3(l)\rightarrow (NH_4)_3PO_4

In such a way, considering the 3 to 1 molar relationship between ammonia and ammonium phosphate, the moles of ammonia result:

n_{NH_3}=0.060mol(NH_4)_3PO_4*\frac{3molNH_3}{1mol(NH_4)_3PO_4}\\n_{NH_3}=0.18molNH_3

Best regards.

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Please help!
koban [17]
A. 599 mg x 1g/1000mg x 1mole/174.24g = 0.003438 moles 
<span>b. 0.003438 moles x 1000 mmoles/mole = 3.438 moles </span>
<span>c. 0.003438 moles/0.741 L = 0.0046 M </span>
<span>d. [K+] = 2 x 0.0046 = 0.0092 M because each mole K2 SO4 yields 2 moles K+ </span>
<span>e. [SO42-] = 0.0046 M </span>
<span>f. 599 mg/0.741 L = 808.4 mg/L = 808 ppm </span>
<span>g. 0.599g/741 ml x 100 ml = 0.08 g/100 ml = 0.08% w/v </span>
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4 0
3 years ago
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Answer is: 0.5 dm³ to dissolve.

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c(CuSO₄) = 0.140 mol/dm³,

V(CuSO₄) = ?

n(CuSO₄) = m(CuSO₄) ÷ M(CuSO₄).

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n(CuSO₄) = 0.07 mol.

V(CuSO₄) = n(CuSO₄) ÷ c(CuSO₄).

V(CuSO₄) = 0.07 mol ÷ 0.14 mol/dm³.

V(CuSO₄) = 0.5 dm³.

4 0
3 years ago
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