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3 years ago

The longer the reaction time is, the the reaction rate is. Reaction time is to reaction rate.

Chemistry

2 answers:

Nostrana [21]3 years ago

6 0

Answer:

False.

Explanation:

Rate of reaction also depends on the number of collision that is being happening in reacting molecules. So concentration of the reactants is also important to decide the rate of reaction.

The rate of reaction is dependent on the concentration as well.

As the concentration of reactants decreases with time number of collisions also decreases .

e-lub [12.9K]3 years ago

3 0

Answer:

From your question you tried to compare reaction rate and time taken(reaction time)

The rate of a reaction is inversely proportional to the time taken(reaction time)

Explanation:

Reaction rate is said to be the decrease in concentration of the reactant or the increase in the concentration of the product per unit time. Reaction rate measures how fast the reactant is used up or how fast the product is formed.

For a given reaction like

Mg(s) + O2(g) → 2MgO(aq)

The reaction rate is derived by measuring how fast the concentration of Mg and O2 decreases or how fast the concentration of MgO increases. Mathematically reaction rate can be expressed as

Reaction rate = Δconcentration/ ΔTime

Reaction rate can be affected by various factors like temperature, reactant concentration and particle size of a solid reactant. Increasing temperature, and increasing reactant concentration increases reaction rate. Decreasing particle size of the solid reactant also increase reaction rate. The collision theory also shed more light on the rate of reaction. How fast the individual molecules of the reactant collide also affect the reaction rate.

The reaction time is the time taken for the reactant to form product. The reaction time is the time taken for the reaction to start and stop. The longer the reaction time, the slower the reaction rate. Fast reaction have short reaction time.

The rate of a reaction is inversely proportional to the time taken(reaction time)

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Need help on last 3 questions

Olin [163]

Answer:

Explanation:

Given data:

Initial volume of balloon = 0.8 L

Initial temperature = 12°C ( 12+273= 285 K)

Final temperature = 300°C (300+273 = 573 K)

Final volume = ?

Solution:

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 0.8 L .573 K / 285 K

V₂ = 458.4 L / 285

V₂ = 1.61 L

Initial pressure = 204 kpa

Initial temperature = 29°C ( 29 + 273 = 302 K)

Final temperature = ?

Final pressure = 300 kpa

Solution:

P₁/T₁ = P₂/T₂

T₂ = T₁P₂/P₁

T₂ = 302 K . 300 kpa / 204 kpa

T₂ = 90600 K/ 204

T₂ = 444.12 K

Given data:

Initial volume = 14 L

Initial pressure = 2.1 atm

Initial temperature = 100 K

Final temperature = 450 K

Final volume = ?

Final pressure = 1.2 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 2.1 atm × 14 L × 450 K / 100 K × 1.2 atm

V₂ = 13230 L / 120

V₂ = 110.25 L

5 0

3 years ago

If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was

Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

$n_{acid}=n_{base}=n_{salt}$

Whereas the moles of the salt are computed as shown below:

$n_{salt}=0.021L*0.68mol/L=0.01428mol$

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

$[salt]=0.01428mol/0.0276L=0.517M$

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

$C_6H_5NH_3^++H_2O\rightleftharpoons C_6H_5NH_2+H_3O^+$

Whose equilibrium expression is:

$Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}$

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

$2.326x10^{-5}=\frac{x^2}{0.517M}$

Whereas x is:

$x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3$

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

$pH=-log(3.47x10^{-3})\\\\pH=2.46$

Regards!

6 0

3 years ago

The following chemical reactants produce the ester ethyl ethanoate (C4H8O2): C2H6O + CH3COOH What type of reaction occurs to mak

nydimaria [60]

Answer:

Esterification reaction

Explanation:

An esterification reaction is an organic reaction involving an organic acid and an alkanol to give an ester or an ethanoate and water

Like the name suggests, an ester is the product formed in an esterification reaction alongside water. It is like a neutralization reaction but this time it solely contains organic molecules. These molecules react with each other to give rise to another organic molecule which is a member of a different homologous series.

Practically, to form ethyl ethanoate, ethanoic acid react with ethanol in the presence of concentrated sulphuric acid which catalyses the reaction.

8 0

3 years ago

Is this the correct answer?

Alona [7]

I believe so, looks like it

8 0

3 years ago

Sort the vocabulary word below. Make sure you have come to live session or watched the 5.03 recording. These words will be impor

Stells [14]

Answer:

Electric Current

This is a flow of electrons (such as the flow of electrons in a wire to light up a lamp).

Insulator

These stop the electricity from flowing (think rubber and glass).

Resistance

This is slowing the flow of electrons (the current) and where some of the electrons' energy gets converted into heat.

Conductor

These allow electricity to flow easily through them (think copper and aluminum).

5 0

3 years ago