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Allushta [10]
3 years ago
10

The longer the reaction time is, the the reaction rate is. Reaction time is to reaction rate.

Chemistry
2 answers:
Nostrana [21]3 years ago
6 0

Answer:

False.

Explanation:

Rate of reaction  also depends on the number of collision that is being happening in reacting molecules. So concentration of the reactants is also important to decide the rate of reaction.

The rate of reaction is dependent on the concentration as well.

As the concentration of reactants decreases with time number of collisions also decreases .

e-lub [12.9K]3 years ago
3 0

Answer:

From your question you tried to compare reaction rate and time taken(reaction time)

The rate of a reaction is inversely proportional to the time taken(reaction time)

Explanation:

Reaction rate is said to be the decrease in concentration of the reactant or the increase in the concentration of the product per unit time. Reaction rate measures how fast the reactant is used up or how fast the product is formed.

For a given reaction like

Mg(s) + O2(g) → 2MgO(aq)

The reaction rate is derived by measuring how fast the concentration of Mg and O2 decreases or how fast the concentration of MgO increases. Mathematically reaction rate can be expressed as

Reaction rate = Δconcentration/ ΔTime

Reaction rate can be affected by various factors like temperature, reactant concentration and particle size of a solid reactant.   Increasing temperature, and increasing reactant concentration increases reaction rate. Decreasing particle size of the solid reactant also increase reaction rate.  The collision theory also shed more light on the rate of reaction. How fast the individual molecules of the reactant collide also affect the reaction rate.

The reaction time is the time taken for the reactant to form product. The reaction time is the time taken for the reaction to start and stop. The longer the reaction time, the slower the reaction rate. Fast reaction have short reaction time.

The rate of a reaction is inversely proportional to the time taken(reaction time)

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A student mixes four reagents together, thinking that the solutions will neutralize each other. The solutions mixed together are
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Answer: Resulting solution will not be neutral because the moles of OH^-ions is greater. The remaining concentration of [OH^-]ions =0.0058 M.

Explanation:

Given,

[HCl]=0.100 M

[HNO_3] = 0.200 M

[Ca(OH)_2] =0.0100 M

[RbOH] =0.100 M

Few steps are involved:

Step 1: Calculating the total moles of H^+ ion from both the acids

moles of H^+ in HCl

HCl\rightarrow {H^+}+Cl^-

if 1 L of HClsolution =0.100 moles of HCl

then 0.05L of HCl solution= 0.05 \times0.1 moles= 0.005 moles    (1L=1000mL)

moles of H^+ in HCl = 0.005 moles

Similarliy

moles of H^+ in HNO_3

HNO_3\rightarrow H^++NO_3^-}

If 1L of HNO_3 solution= 0.200 moles

Then 0.1L of HNO_3 solution= 0.1 \times 0.200 moles= 0.02 moles

moles of H^+ in HNO_3 =0.02 moles

so, Total moles of H^+ ions  = 0.005+0.02= 0.025 moles     .....(1)

Step 2: Calculating the total moles of [OH^-] ion from both the bases

Moles of OH^-\text{ in }Ca(OH)_2

Ca(OH)_2\rightarrow Ca^2{+}+2OH^-

1 L of Ca(OH)_2= 0.0100 moles

Then in 0.5 L Ca(OH)_2 solution = 0.5 \times0.0100 moles = 0.005 moles

Ca(OH)_2 produces two moles of OH^- ions

moles of OH^- = 0.005 \times 2= 0.01 moles

Moles of OH^- in RbOH

RbOH\rightarrow Rb^++OH^-

1 L of RbOH= 0.100 moles

then 0.2 [RbOH] solution= 0.2 \times 0.100 moles = 0.02 moles

Moles of OH^- = 0.02 moles

so,Total moles of OH^- ions = 0.01 + 0.02=0.030 moles      ....(2)

Step 3: Comparing the moles of both H^+\text{ and }OH^- ions

One mole of H^+ ions will combine with one mole of OH^- ions, so

Total moles of H^+ ions  = 0.005+0.02= 0.025 moles....(1)

Total moles of OH^- ions = 0.01 + 0.02=0.030 moles.....(2)

For a solution to be neutral, we have

Total moles of H^+ ions = total moles of OH^- ions

0.025 moles H^+ will neutralize the 0.025 moles of OH^-

Moles of OH^- ions is in excess        (from 1 and 2)

The remaining moles of OH^- will be = 0.030 - 0.025 = 0.005 moles

So,The resulting solution will not be neutral.

Remaining Concentration of OH^- ions = \frac{\text{Moles remaining}}{\text{Total volume}}

[OH^-]=\frac{0.005}{0.85}=0.0058M

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