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Diano4ka-milaya [45]
3 years ago
9

.What threatens the newly hatched chicks?

Chemistry
2 answers:
marysya [2.9K]3 years ago
3 0

Answer:

rats. that's all i know of Just about everything except the mother hen if they are natural hatch. Even when you incubate them there are threats. The healthy chicks will mob the weak ones, the older chicks (even by a day) will pick on the younger ones. Temperature extremes will threaten them as they need warm, humid conditions with gradual drops in surrounding temps in the brooder box. Early disease is sometimes a problem and all chicks should be started on medicated chick feed for the first few weeks to prevent several digestive diseases. Even the water dispenser can be a threat as newly hatched chicks will immerse themselves in an open water container so care should be taken to supply water in a self feeding covered dish.

Explanation:

AlekseyPX3 years ago
3 0

Answer:

im pretty sure its just rats and the mother hen if the chick isn't healthy

Explanation:

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Sulfur and magnesium both have two valence electrons.<br> a. True<br> b. False
Nezavi [6.7K]
It would be false sulfur has 6 
3 0
3 years ago
Enter the correct 4 digit code (no spaces)
Airida [17]
3618 is the numbers for the graph
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A. 2.0x1024 atoms of S to moles (3.3)
Fynjy0 [20]

3.3 moles of sulfur

Explanation:

To find the number of moles knowing the number of atoms we use Avogadro's number to formulate the following reasoning:

if in         1 mole of sulfur (S) there are 6.022 × 10²³ atoms of sulfur (S)

then in   X moles of sulfur (S) there are 2 × 10²⁴ atoms of sulfur (S)

X = (1 × 2 × 10²⁴) / (6.022 × 10²³)

X = 3.3 moles of sulfur

Learn more about:

Avogadro's number

brainly.com/question/1445383

#learnwithBrainly

5 0
3 years ago
Write a balanced equation for the complete combustion of each compound. a. formaldehyde (CH2O(g)) b. heptane (C7H17(l)) c. benze
Yuri [45]

Answer:

a. formaldehyde (CH₂O(g)): CH₂O(g) + O₂(g) → CO₂(g) + H₂O(g)

b. heptane (C₇H₁₇(l)): 4C₇H₁₇(l) + 45O₂(g) → 28CO₂(g) + 34H₂O(g)

c. benzene (C6H6(l))​: C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3 H₂O(g)

Explanation:

In a reaction of combustion, a hydrocarbon compound (composed of C, H and O) reacts with oxygen gas (O₂). The <u>complete</u> combustion of a hydrocarbon - such as formaldehyde, heptane, and benzene - produces carbon dioxide (CO₂) and water (H₂O).  

Thus, we write the reactants and products for each combustion reaction and then we balance the atoms: C, H, and O.

a. formaldehyde (CH₂O(g)):

CH₂O(g) + O₂(g) → CO₂(g) + H₂O(g)

The chemical equation is already balanced with the coefficients 1: we have the same number of C atoms (1), H (2) and O (3) on both sides of the equation.

b. heptane (C₇H₁₇(l)):

C₇H₁₇(l) + O₂(g) → CO₂(g) + H₂O(g)

Here we have to write a coefficient 28 for CO₂ to balance the C atoms in the products side, and for C₇H₁₇ we write 28/4 = 7. With similar reasoning we found the coefficients for O₂ and H₂O:

4C₇H₁₇(l) + 45O₂(g) → 28CO₂(g) + 34H₂O(g)

c. benzene (C6H6(l))​:

C₆H₆(l) +  O₂(g) → CO₂(g) +  H₂O(g)

First, we write a coefficient of 6 for CO₂ to balance the C atoms. Then, we have to balance H atoms: we write a coefficient 3 in H₂O. Now, we have 12 + 3 = 15 atoms of O on the reactants side. So, we write a half of these number of atoms in the coefficient for O₂: 15/2. We obtain the balanced equation:

C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3 H₂O(g)

5 0
2 years ago
Scientific predictions should be made from:
VladimirAG [237]

Answer:

studies

Explanation:

if they get plenty of studies then they get it

3 0
3 years ago
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