Answer:
The following relationship makes this possible: 1 mole of any gas at standard temperature and pressure (273 K and 1 atm) occupies a volume of 22.4 L.
Explanation:
The answer is ultraviolet
Answer:
3.6667
Explanation:
<u>For helium gas:</u>
Using Boyle's law
Given ,
V₁ = 3.0 L
V₂ = 9.0 L
P₁ = 5.6 atm
P₂ = ?
Using above equation as:
<u>The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm</u>
<u>For Neon gas:</u>
Using Boyle's law
Given ,
V₁ = 4.5 L
V₂ = 9.0 L
P₁ = 3.6 atm
P₂ = ?
Using above equation as:
<u>The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm</u>
<u>Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.</u>