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SVEN [57.7K]
3 years ago
15

Glucose and amino acids are reabsorbed from the glomerular filtrate by the __________.

Chemistry
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:

Amino acids, along with glucose, are reabsorbed in the glomerular system with a passive or active mechanism as the fluid travels through the entire renal tubular system and enters the circulation again.

Active mechanisms are those that require expenditure of energy, that is, expenditure of the energy currency, while the passive ones do not, they occur through spontaneous non-energy processes such as osmosis, the osmotic gradient and the difference in concentrations in different compartments.

Explanation:

Glomerular filtration is the regulator of the excretion of metabolites and toxic molecules or not necessary for our body. That is why if the amino acid values ​​are high as well as those of glucose in urine, we will be facing a pathology.

If glucose is increased, it is because there is a glycemic peak in blood volume, hence possible diabetes.

And if the amino acids are increased, we could be facing an autoimmune or proteolytic pathology where a large amount of body proteins such as muscle proteins would be breaking down and releasing the amino acids that make it up, this phenomenon usually appears in those people who suffer from rhabdomyolysis in expenses very intense energy sources not appropriate.

On the other hand, glomerular filtration occurs in the kidney and is carried out by the nephron, which is the functional unit of the kidney, within it there is a specific tubular system in collection, absorption and reabsorption, added to the presence of Bowman's capsule.

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What is the mass of heavy water, D2O(l), produced when 7.60 g of O2(g) reacts with excess D2(g)?
Rina8888 [55]
<h3>Answer:</h3>

19.026 g

<h3>Explanation:</h3>

The reaction between D₂ and O₂ is given by the equation;

2D₂(g) + O₂(g) → 2H₂O(l)

We are given;

Mass of oxygen (O₂) that reacted as 7.60 g

We are required to calculate the mass of D₂O produced;

<h3>Step 1: Calculate the moles of O₂ used (limiting reactant)</h3>

To calculate the number of moles we divide mass by the molar mass.

Moles = mass ÷ Molar mass

Molar mass of O₂ is 16.0 g/mol

Therefore;

Moles = 7.60 g ÷ 16.0 g/mol

         = 0.475 moles

<h3>Step 2: Calculate the moles of D₂O produced </h3>

From the equation, 1 mole of oxygen reacts to produce 2 moles of D₂O

Thus, the mole ratio of O₂ : D₂O is 1 : 2

Therefore, moles of D₂O = Moles of O₂ × 2

                                          = 0.475 moles × 2

                                          = 0.95 moles

<h3>Step 3: Calculate the mass of heavy water produced</h3>

Mass = Number of moles × Molar mass

Molar mass of heavy water = 20.0276 g/mol

Therefore;

Mass of heavy water = 0.95 moles × 20.0276 g/mol

                                   = 19.026 g

Hence, the mass of heavy water produced is 19.026 g

3 0
4 years ago
What is the force called that is applied to an object and it's NOT opposite and/or equal?
jasenka [17]

i think the answer would be velocity.

8 0
3 years ago
Read 2 more answers
An 8.42 g piece of metal with a specific heat of 1.020 J g-1 k-1 wasn't heated to an unknown temperature. The metal was then pla
ANTONII [103]

Answer:

T = 61.344\,^{\textdegree}C

Explanation:

The heat received by water is equal to the heat rejected by the piece of metal. That is to say:

-Q_{piece} = Q_{water}

(8.42\,g) \cdot \left(1.020\,\frac{J}{g\cdot ^{\textdegree}C}  \right) \cdot (T - 20.40\,^{\textdegree}C)= (44.2\,g)\cdot \left(4.187\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (20.40\,^{\textdegree}C-18.50\,^{\textdegree}C)

\left(8.588\,\frac{J}{^{\textdegree}C} \right)\cdot (T-20.40\,^{\textdegree}C) = 351.624\,J

The initial temperature of the piece of metal is:

T = 61.344\,^{\textdegree}C

4 0
3 years ago
Read 2 more answers
Richard and Brooke's teacher tells them to place 30 marbles in an 8-inch
Fynjy0 [20]

Answer:

The correct answer is - They gently shake the pan causing the marbles to move back and forth.

Explanation:

When water is heated the molecules present in its liquid state start to move and vibrate faster and allows the water to expand and increase in volume. If the heat is continuously applied to the water its molecules move even faster and escape in the form of molecules of vapor to the atmosphere.

To exhibit this phenomenon by the marble and pan, Richard and Brooke should gently shake the pan causing the marbles to move back and forth which shows faster vibration and movement of molecules.

3 0
3 years ago
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Artist 52 [7]

Answer: sandbars

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