Labor productivity is normally measured by (c) <u>dividing total real domestic output by the number of workers or by the number of</u><u> labor hours.</u>

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<h3>What is Labour productivity?</h3>

The total volume of production (measured in terms of Gross Domestic Product, GDP) produced per unit of labor (measured in terms of the number of employed workers or hours worked) during the course of a specific time reference period is what is referred to as labor productivity.
Divide the total output by the total labor hours to find the labor productivity of a nation.

What is labour productivity in India?

A measurement of labor output is labor productivity.
Hourly productivity metrics are used. The actual Gross Domestic Product (GDP) produced by labor in an hour is what is referred to as labor productivity in macroeconomics.
An important component of a business's overall growth is labor productivity.

Learn more about labour productivity

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A random sample of 85 sixth-graders in a large city take a course designed to improve scores on a reading comprehension test. Ba

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Answer:

$12.6 < \mu < 14.8$

For this case we can find the margin of error like this:

$ME= \frac{14.8-12.6}{2}= 1.1$

Since we need to divide the width of the interval by 2.

And now with the margin of error we can find the sample mean with any of the two following ways:

$12.6 +1.1=13.7$

$14.8-1.1=13.7$

So for this case the correct answer would be:

A. Sample Mean = 13.7; Margin of Error = 1.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=85-1=84$

We know that the confidence interval is given by: