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3 years ago

14

Rectangle A measures 8 inches by 4 inches. Rectangle B is a scaled copy

1 answer:

Savatey [412]3 years ago

5 0

Rectangle B = 56inches by 28inches
It’s pretty easy you just multiply 8 by 7 and 4 by 7.

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Which of the following sets could be the sides of a right triangle?

MArishka [77]

In a right triangle the sum of the squares of the lengths of two shorter sides is equal to the square of the length of the longest side.

a.
$2^2+3^2=(\sqrt{13})^2 \\
4+9=13 \\
13=13 \\ true$

b.
$2^2+2^2=4^2 \\
4+4=16 \\
8=16 \\
not \ true$

c.
$1^2+(\sqrt{3})^2=2^2 \\
1+3=4 \\
4=4 \\
true$

The answer is A and C.

5 0

3 years ago

Read 2 more answers

Geometry help needed! Thanks.

VMariaS [17]

EN = NE

Answer

D. last one

NE

4 0

3 years ago

Special right triangles

telo118 [61]

Answer: please find the attached files

Step-by-step explanation:

A unit circle formula and special triangle of 45, 30 and 60 degrees can be used to solve the problem.

Please find the attached files for the solution

6 0

3 years ago

Solve the inequality.

marysya [2.9K]

Answer:

$\huge x > \frac{7}{3} \\$

Step-by-step explanation:

$8( \frac{1}{2} x - \frac{1}{4} ) > 12 - 2x \\$

<u>Expand the terms in the bracket</u>

That's

$8( \frac{1}{2} x) - 8( \frac{1}{4} ) > 12 - 2x \\ 4x - 2 > 12 - 2x$

Move -2x to the other side of the inequality

$4x + 2x - 2 > 12 \\ 6x - 2 > 12$

<u>Move - 2 to the other side of the inequality</u>

$6x > 12 + 2 \\ 6x > 14$

Divide both sides by 6

$\frac{6x}{6} > \frac{14}{6} \\$

We have the final answer as

$x > \frac{7}{3} \\$

Hope this helps you

5 0

3 years ago

Find all the zeroes of the equation and show your work<br> -3x^4 + 27x^2 + 1200 = 0

s344n2d4d5 [400]

Answer:i try checking the internet

Step-by-step explanation:

fgnjjjjjjjjcbkm/gijw'

eofsdkm;grfbkm

6 0

3 years ago

Read 2 more answers