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4 years ago

6

Supposing we launched a very fast dart from the Space Shuttle, pointed in some direction away from any planet, so that it could

travel beyond the solar system. What would it be most likely to hit first after traveling outward for a while

1 answer:

natulia [17]4 years ago

5 0

Rocks and minerals kind of dust like, that’s really all there is in space.

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A 1.8-kg object moves in the x direction according to the following function:

DanielleElmas [232]

Well, if the position is <u> x(t) = 2t² + 3t - 5</u>

then the speed is x ' (t) = 4t + 3 (first derivative of 'x' wrt 't')

and the acceleration is x ' ' (t) = 4 (second derivative of 'x' wrt 't')

Apparently, then, the acceleration is constant, and is not a function of time.

After 2.7 seconds or 2.7 years, the acceleration is 4 .

Force = (mass) x (acceleration)

Force = (1.8) x (4)

<em>Force = 7.2 newtons </em>

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3 years ago

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kvasek [131]

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3 years ago

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4 years ago

The illustration above depicts a spring being compressed and then released. Changes in both potential and kinetic energy occur d

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3 years ago

Read 2 more answers

A block with mass m =6.4 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.28 m.

Zanzabum

Answer

given,

mass of block (m)= 6.4 Kg

spring is stretched to distance, x = 0.28 m

initial velocity = 5.1 m/s

a) computing weight of spring

k x = m g

$k = \dfrac{mg}{x}$

$k = \dfrac{6.4 \times 9.8}{0.28}$

k = 224 N/m

b) $f = \dfrac{\omega}{2\pi}$

$\omega = \sqrt{\dfrac{k}{m}}= \sqrt{\dfrac{224}{6.4}} = 5.92 \ rad/s$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{224}{6.4}}$

$f =0.94\ Hz$

c) $v_b = -v cos \omega t$

$v_b = -5.1 \times cos (5.92 \times 0.42)$

$v_b = 4.04\ m/s$

d) $a_{max} = v \omega$

$a_{max} = 4.04 \times 5.92$

$a_{max} =23.94\ m/s^2$

e) $Y =- A sin (\omega t)$

$A = \dfrac{v}{\omega}$

$A = \dfrac{4.04}{5.92}$

A = 0.682 m

$Y =- 0.682 \times sin (5.92 \times 0.42)$

$Y =- 0.42$

Force = $m \omega^2 |Y|$

= $6.4 \times 5.92^2\times 0.42$

F = 94.20 N

4 0

4 years ago