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erastova [34]
3 years ago
15

What is the fundamental unit for measuring mass in the metric system ?

Physics
2 answers:
goldenfox [79]3 years ago
6 0
Kilogram(kg)
It's not the SI unit of mass in the metric system however.
Salsk061 [2.6K]3 years ago
4 0

Answer:

The correct answer is gram (g).

Explanation:

The metric system uses grams (g) as the fundamental unit of measurement of mass. This system applies the idea that units increase and decrease by a power of 10. This means that a kilogram (kg) is 1000 times heavier than a gram (g), and a gram is 1000 times heavier than a milligram (mg).

Have a nice day!

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Lora (of mass 47.4 kg) is an expert skier. She
Harrizon [31]

Answer:

Kinetic energy is 242.7 Joule

Explanation:

m = 47.4 kg

v = 3.2m/s²

Now,

K.E. = 1/2 × m × v²

or, K.E. = 1/2 × 47.4 × 3.2²

or, K.E. = 242.7 Joule

6 0
2 years ago
According to Newton's third law of motion, which are equal
dem82 [27]

As per Newton's III law

Every action force that is applied on an object must be equal and opposite to reaction force applied by that object.

It can be said that when we apply any force on an object then this applied force is known as action force and at the same time that object also apply an opposite direction force on us which is known as reaction force having same magnitude.

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7 0
3 years ago
You have a two-wheel trailer that you pull behind your ATV. Two children with a combined mass of 77.2 kg hop on board for a ride
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To solve this problem it is necessary to apply the kinematic equations of motion and Hook's law.

By Hook's law we know that force is defined as,

F= kx

Where,

k = spring constant

x = Displacement change

PART A) For the case of the spring constant we can use the above equation and clear k so that

k= \frac{F}{x}

k = \frac{mg}{x}

k= \frac{77.2*9.8}{0.0637}

k = 11876.92N/m

Therefore the spring constant for each one is 11876.92/2 = 5933.46N/m

PART B) In the case of speed we can obtain it through the period, which is given by

T = \frac{2\pi}{\omega}

Re-arrange to find \omega,

\omega = \frac{2\pi}{T}

\omega = \frac{2\pi}{2.14}

\omega = 2.93rad/s

Then through angular kinematic equations where angular velocity is given as a function of mass and spring constant we have to

\omega^2 = \frac{k}{m}

m = \frac{k}{\omega^2}

m = \frac{ 11876.92}{2.93}

m = 4093.55Kg

Therefore the mass of the trailer is 4093.55Kg

PART C) The frequency by definition is inversely to the period therefore

f = \frac{1}{T}

f = \frac{1}{2.14}

f = 0.4672 Hz

Therefore the frequency of the oscillation is 0.4672 Hz

PART D) The time it takes to make the route 10 times would be 10 times the period, that is

t_T = 10*T

t_T = 10 *2.14s

t_T = 21.4s

Therefore the total time it takes for the trailer to bounce up and down 10 times is 21.4s

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3 years ago
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3 years ago
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What is Vatiable Velocity?​
Allushta [10]

Answer:

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