Answer:
If you were to inject air into space what would have happen?
Explanation:
In order for air to defy gravity, it would require atmospheric pressure. But air dosen't defy gravity unless it has the support of atmospheric pressure.
Considering the deuterium-tritium fusion reaction with the tritium nucleus at rest: ¹₂H + ¹₃H → ²₄He + ⁰₁n the electric potential energy (in electron volts) at this distance is 17.58MeV
<h3>How is the electric potential energy of deuterium-tritium fusion reaction calculated?</h3>
The reaction is ¹₂H + 1₃H → ²₄He + ⁰₁n
Value of Q = (Mass of ¹₂H + Mass of ¹₃H - Mass of ²₄He- Mass of n) x 931 MeV
Mass of ¹₂H = 2.014102
Mass of ¹₃H = 3.016049
Mass of ²₄He = 4.002603
Mass of n = 1.00867
Therefore Value of Q = [2.014102+3.016049−4.002603−1.00867] × 931 MeV
Therefore Value of Q = 0.01887 × 931 MeV
= 17.58MeV
To learn more about deuterium-tritium fusion reaction, refer
brainly.com/question/9054784
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