<h2>The time taken is 1 second </h2>
Explanation:
Suppose the first diamond falls for t seconds
The downward displacement S₁ = u t +
g t²
here u = 0 , because it was at rest initially
Thus S₁ =
g t² I
Similarly second diamond moves for time ( t - 0.9 ) sec
The distance covered by it is
S₂ =
g (t - 0.9 )²
The separation between the two is 13 m
Thus S₁ - S₂ = 13 m
g t² -
g t² + 0.9 g t - 0.4 g = 13
or 9 t = 13 - 4 = 9
Hence t = 1 sec
Answer:
0 is your answereeeeerrrrr
Explanation:
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The density of an object is given by:
D = M/V
D = density, M = mass, V = volume
The volume of the cube V is given by:
V = s³
where s = side length
Make a substitution:
D = M/s³
Given values:
M = 20kg, s = 20×10⁻²m
Plug in and solve for D:
D = 20/(20×10⁻²)³
D = 2500kg/m³