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2 years ago

I NEED HELP WITH JUST 2 QUESTIONS PLEASE!!!! oops sry

Mathematics

2 answers:

vodka [1.7K]2 years ago

7 0

Answer: 10 john is right

Step-by-step explanation: 11 +7 - 2 x 3 +8

$11 + 7 - 2 x 3 + 8 \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\$

Artist 52 [7]2 years ago

4 0

Answer:

PAGE 1

A. Since PEMDAS 2*3 first

2*3 = 6

then 8/2

8/2 = 4

leaving

11 + 7 - 6 + 4

next 11 + 7

11 + 7 = 18

18 - 6 + 4

18 - 6 = 12

12 + 4 = 16

your answer is 16

B. No because John did not complete his problem correctly. The right answer is 16.

PAGE 2

A. Because of PEMDAS 4 * 12 first

4 * 12 = 48

then 48/3 = 16

your equation comes to

48 + 16 -15

then do

48 + 16 = 64

64 - 15 = 49

the answer is 49

B. If you don't do PEMDAS it can cost you the right answer.

See what answer you get when you don't do PEMDAS and just complete the equation left to right

48 + 4 = 52

52 * 12 = 624

624/3 = 208

208 - 15 = 193

the wrong non-PEMDAS used answer would then be 193

hope this helps:)

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3 years ago

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daser333 [38]

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3 years ago

Which of the following expressions is a factor of the polynomial x 2 +3/2x-1

Elodia [21]

Answer:

$\large \boxed{\sf \ \ \ (x+2)(x-\dfrac{1}{2}) \ \ \ }$

Step-by-step explanation:

Hello,

let's solve

$x^2+\dfrac{3}{2}x-1=0\\\\ 2x^2+3x-2=0 \ \text{multiply by 2}\\\\\\$

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There are two solutions

$x_1=\dfrac{-3-\sqrt{25}}{4}\\\\x_1=\dfrac{-3-5}{4}\\\\x_1=\dfrac{-8}{4}\\\\\boxed{x_1=-2}$

And

$x_2=\dfrac{-3+\sqrt{25}}{4}\\\\x_2=\dfrac{-3+5}{4}\\\\x_2=\dfrac{2}{4}\\\\\boxed{x_2=\dfrac{1}{2}}$

So we can write

$x^2+\dfrac{3}{2}x-1\\\\=(x-x_1)(x-x_2)\\\\=(x+2)(x-\dfrac{1}{2})$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago