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Alchen [17]
3 years ago
7

There are n gallons of oil. After m gallons have been used then, in terms of m and n, what percent of oil remains? What percent

was used? PLZ HELP
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
8 0

Answer:

remains is (n-m/n)*100 used is (m/n)*100

Step-by-step explanation:

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How do the perimeters of the rectangles compare?
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6 0
3 years ago
Find a1 and d for an arithmetic sequence with these terms. a3=-8 and a7=32
Arte-miy333 [17]
We know that
the formula for the <span>arithmetic sequence is
</span><span>an = a1 + (n - 1)*d
where
a1  is the first term
n is the numbers of terms

for n=3   a3=-8
-8=a1+(3-1)*d-----> -8=a1+2*d-----> equation 1

for n=7   a7=32
-32=a1+(7-1)*d----> -32=a1+6*d----> equation 2

multiply equation 2 by -1-----> 32=-a1-6*d------> equation 3

add equation 1 and equation 3
</span>-8=a1+2*d
32=-a1-6*d
----------------
24=-4*d------> d=-6
-8=a1+2*(-6)    (substitute the value of d in equation 1)
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the answer is
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<span>

</span>
4 0
3 years ago
Please solve this question for a
ohaa [14]

Answer:

<h2>a =  \frac{8A}{\pi {r}^{2} }  + 1 \\</h2>

Step-by-step explanation:

A =  \frac{1}{8} \pi {r}^{2} (a - 1) \\

First of all multiply through by 8 to eliminate the fraction

That's

8A = 8 \times  \frac{1}{8} \pi {r}^{2} (a - 1) \\8 A = \pi {r}^{2} (a - 1)

<u>Divide both sides by πr²</u>

\frac{8A}{\pi {r}^{2} }  =  \frac{\pi {r}^{2}(a - 1) }{\pi {r}^{2} }  \\ a - 1 =  \frac{8A}{\pi {r}^{2} }

Move 1 to the other side of the equation to make a stand alone

We have the final answer as

a =  \frac{8A}{\pi {r}^{2} }  + 1 \\

Hope this helps you

7 0
3 years ago
Read 2 more answers
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