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Alchen [17]
3 years ago
7

There are n gallons of oil. After m gallons have been used then, in terms of m and n, what percent of oil remains? What percent

was used? PLZ HELP
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
8 0

Answer:

remains is (n-m/n)*100 used is (m/n)*100

Step-by-step explanation:

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What is the range of the function f(x) = -4|x + 1| − 5?
lukranit [14]

Answer:

answer is A

Step-by-step explanation:

hope that helps

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=x%20%2B%207%20%20%3C%20%20-%202" id="TexFormula1" title="x + 7 &lt; - 2" alt="x + 7 &lt; -
vladimir1956 [14]
First one because when you subtract 7 u keep the var. x alone and isolate it.
5 0
3 years ago
Suppose an airplane traveling in a circle at 138 m/s can turn in a circle with as much as 69.6 m/s of centripetal acceleration.H
Oksanka [162]

Answer: A. 9567m

i hope i'm correct let me know if i'm wrong

6 0
3 years ago
Sales variances may be computed in a manner similar to cost variances–that is, computing both price and volume variances.
Sholpan [36]

Answer:

The answer is True.

Step-by-step explanation:

Sales variance is computed in same manner as cost variance that is computing both price and volume variance. However interpretation of end result will not be same. For example in material price variance if

A = actual purchase price = $ 4, B = standard purchase price= $ 5 and Qt= quantity purchased = 500 units then

Material price varaince = 500 (5-4) = 500,

This gives us favourable price variance of 500 dollars. However in sales price variance if

A = actual sales price = $ 4, B = standard sale price= $ 5 and Qt= quantity sold = 500 units then

Sale price varaince = 500 (5-4) = (500)

This gives us unfavourable sales price variance of 500 dollars.

This show that formulas to compute variances are same but sale price decrease give us un favorable variance and cost price decrease gives us favorable price variance and vice versa.

6 0
3 years ago
gde Sta manut Stree and Lincoln Set orm a right triangle with a trafic light at each intersection. The distance between the traf
earnstyle [38]

The diagram is of a right triangle with

Hypotenuse = 233

One leg of the triangle = 105

Another Leg = <em>we have to find</em>

<em />

<em />

Pythagorean Theorem can be written as:

\text{Leg}^2+\text{AnotherLeg}^2=\text{Hypotenuse}^2

Thus, we can write:

\begin{gathered} 105^2+\text{AnotherLeg}^2=233^2 \\ \text{AnotherLeg}^2=233^2-105^2 \\ \text{AnotherLeg}^2=43264 \\ \text{AnotherLeg}=\sqrt[]{43264} \\ \text{AnotherLeg}=208\text{ ft} \end{gathered}

Thus,

The distance between the traffic lights on Walnut Street is:

208 feet
4 0
1 year ago
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