Test tubes, spot and/or well plate will be used to combine substances in bottles and form a reaction is referred to a true statement.
<h3>What is a Chemical reaction?</h3>
This is the reaction which involves substances known as reactants combining new substances which are referred to as products. This is usually done in the laboratory and equipment and tools such as test tubes, thermometer etc are used.
Test tubes, spot and/or well plate are often used to combine substances in bottles and form a reaction which must be handled with care to ensure it doesn't spill.
This is therefore the reason why the option true was chosen as the most appropriate choice.
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Let's eliminate these one by one.
The first pair would not be the same, as X would most likely be in group IA, and Y would be in group VIIA, because of their tendency to gain and lose electrons.
The second pair would also violate the same rule, but X would most likely be in group IIA, and Y would most likely be in group VIA.
The third pair would not be the same, as X is most likely in group VIIA, and since Y has eight valence electrons, it is most likely a noble gas.
The final pair has X with atomic number 15, making it phosphorous. Phosphorous wants to gain 3 electrons to have a full octet of 8 outer "valence" electrons, and Y would also like to gain 3 electrons. This means it is possible that the final pair would be in the same group.
It is about equal to the mass of the neutron. So, most people just say that they have the same mass.
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Answer:
I think acetone has more because water is just H20
Answer:
Explanation:
1. find the molar mass (amu) of each element and add them to get the whole molar mass.
2. divide the 1 element molar mass with the whole molar mass
3. multiple by 100 and that gives you the % composition.
<h2><u><em>56-57: NaCl</em></u></h2>
1. Na(22.99amu) + Cl (35.453amu)=58.443
2(Na):
= .393
2(Cl):
= .607
3(Na): .393 * 100=39.3%
3(Cl): .607 * 100= 60.7%
<h2><u>58-60 </u>

<u /></h2>
1. K: (39.098)(2)=78.196
_ C: (12.011)(1)= 12.011
_O: (15.99)(3) = 47.997
78.196+12.011+47.997= 138.204
2:K:
= .566 <u>Step </u>3: (.566)(100)= 56.6%
2: C:
= .087 <u>Step 3</u>: (.087)(100)= 8.7%
2: O:
= .347 <u>Step 3</u>: (.347)(100) = 34.7%
<h2>
61-62 
</h2>
1. Fe (55.845)(3)= 167.535
_ O (15.999)(4) = 63.996
167.535+63.996=231.531
2: Fe:
= .724 Step 3: (.724)(100)= 72.4%
2: O :
= .276 Step 3: (.276)(100) = 27.6%
<h2>63-65

</h2>
1.
C(12.011*3)=36.033
H(1.008*5)=5.04 + (1.008*3)=3.024 so its 8.064
O(15.999*3)=47.997
add them: 92.094
2: C:
= .391 Step 3: (.391)(100) = 39.1%
2: H:
= .088 step 3: (.088)(100) = 8.8%
2: O:
= .521 step 3: (.521)(100) = 52.1%