Answer:
The number of electrons is the atomic number
Four electron shells cause both of them are on the 4th period.
Answer:
h
Explanation:
hence co2 has a linear molecular goemetry with the bond angles of 180 degrees and symmetric distribution of electrons. CO2 Lewis structure, molecular goemetry hybridization in carbon dioxide molecule, the central carbon atom is surrounded by two areas of electrons density
1 mol --- 22,4 dm³
2,1 mol --- X
X = 2,1×22,4
X = 47,04 dm³ = 47,04 L
C)
Answer:
the rate of change of
= 10.0 M/s
the rate of change of
= 20.0 M/s
Explanation:
Given that
= 20.0 M/s
The equation for the reaction can be written as:

The rate of change of
can be calculated as:
![\frac{-1}{2} \frac{d[NO]}{dt} = \frac{d[N_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7D%20%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D%20%3D%20%5Cfrac%7Bd%5BN_2%5D%7D%7Bdt%7D)
![\frac{-1}{2} (-20.0M/s)= \frac{d[N_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7D%20%28-20.0M%2Fs%29%3D%20%5Cfrac%7Bd%5BN_2%5D%7D%7Bdt%7D)
![-1 *-10.0M/s= \frac{d[N_2]}{dt}](https://tex.z-dn.net/?f=-1%20%2A-10.0M%2Fs%3D%20%5Cfrac%7Bd%5BN_2%5D%7D%7Bdt%7D)
![10.0M/s= \frac{d[N_2]}{dt}](https://tex.z-dn.net/?f=10.0M%2Fs%3D%20%5Cfrac%7Bd%5BN_2%5D%7D%7Bdt%7D)
![\frac{d[N_2]}{dt}= 10.0M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BN_2%5D%7D%7Bdt%7D%3D%2010.0M%2Fs)
∴ the rate of change of
= 10.0 M/s
The rate of change of
can be calculated as:
![\frac{-1}{2} \frac{d[NO]}{dt} = \frac{+1}{2} \frac{d[H_2O]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7D%20%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D%20%3D%20%5Cfrac%7B%2B1%7D%7B2%7D%20%20%5Cfrac%7Bd%5BH_2O%5D%7D%7Bdt%7D)
![\frac{-1}{2} (-20.0M/s)= \frac{+1}{2} \frac{d[H_2O]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7D%20%28-20.0M%2Fs%29%3D%20%5Cfrac%7B%2B1%7D%7B2%7D%20%20%5Cfrac%7Bd%5BH_2O%5D%7D%7Bdt%7D)
![10.0 M/s= \frac{+1}{2} \frac{d[H_2O]}{dt}](https://tex.z-dn.net/?f=10.0%20M%2Fs%3D%20%5Cfrac%7B%2B1%7D%7B2%7D%20%20%5Cfrac%7Bd%5BH_2O%5D%7D%7Bdt%7D)
![10.0 M/s*2= \frac{d[H_2O]}{dt}](https://tex.z-dn.net/?f=10.0%20M%2Fs%2A2%3D%20%20%5Cfrac%7Bd%5BH_2O%5D%7D%7Bdt%7D)
![\frac{d[H_2O]}{dt} = 20.0 M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BH_2O%5D%7D%7Bdt%7D%20%3D%2020.0%20M%2Fs)
∴ the rate of change of
= 20.0 M/s