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Margaret [11]
4 years ago
14

Which of the following pairs of elements could possibly be in the same group? X has a 1+ ion; Y has a 1- ion. X tends to form a

2+ ion; Y tends to gain two electrons. X will tend to gain one electron; Y has eight valence electrons. X has an atomic number 15; Y forms a 3- ion.
Chemistry
2 answers:
exis [7]4 years ago
5 0
Let's eliminate these one by one.
The first pair would not be the same, as X would most likely be in group IA, and Y would be in group VIIA, because of their tendency to gain and lose electrons.
The second pair would also violate the same rule, but X would most likely be in group IIA, and Y would most likely be in group VIA.
The third pair would not be the same, as X is most likely in group VIIA, and since Y has eight valence electrons, it is most likely a noble gas.
The final pair has X with atomic number 15, making it phosphorous. Phosphorous wants to gain 3 electrons to have a full octet of 8 outer "valence" electrons, and Y would also like to gain 3 electrons. This means it is possible that the final pair would be in the same group.
White raven [17]4 years ago
3 0

Answer is: X has an atomic number 15; Y forms a 3- ion.

1)  X has a 1+ ion; Y has a 1- ion is not correct, because X is probably metal (lost one electron, group 1) and Y is nonmetal (gain one electron, group 17).

2) X tends to form a 2+ ion; Y tends to gain two electrons is not correct, because X lost two electrons (probably metal from group 2).

3) X will tend to gain one electron; Y has eight valence electrons is not correct, because X is probably from group 17 and Y is noble gas (group 18).

4) Y is phosphorus (atomic number 15, group 15) and Y is nonmetal from group 15.

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The value of Henry's law constant for oxygen in water at 242C is 1.66 x 1 ox M/torr. b. c. Calculate the solubility of oxygen in
DochEvi [55]
25ca an the oxygen gas is 2 atom ur mum
4 0
3 years ago
Increased use of incineration is sometimes advocated as a safe way to dispose of chemical waste. But opponents of incineration p
pochemuha

Answer:

Option A is correct.

At the two incinerators at which leaks were reported, staff had had only cursory training on the proper procedures for incinerating chemical waste.

Explanation:

The main aim of the argument presented is to talk down the use of burning by incinerators method to dispose chemical waste. The argument presents great points in that there were 40 incidents at two existing commissioned incinerators in the last year where unexpected releases of dangerous chemical agents happened.

So, basically, the argument is all about how the high frequency of the unsuspected release of dangerous chemical agents should discourage this method of chemical waste disposal.

The argument then concluded that if more chemical waste are disposed using the burning by incinerator method, there will be more unsuspected release of dangerous chemicals.

We are then required to find the statement that most weakens the conclusion that there will be more toxic releases if more chemical waste are burned.

Analysing the Statements one by one

Statement A

This statement provides a possible reason for this high frequency of dangerous chemical releases. It states that the staff haven't been properly trained. So, this means that properly training the staff should most likely lead to lesser cases of toxic releases into the environment.

This is the statement that most weakens the conclusion.

Statement B

The conclusion wasn't about the incinerator method being the safest method. It was about whether increased incineration would lead to more toxic relaeses. So, this doesn't affect the conclusion.

Statement C

This statement says that incineration can be increased without building new incinerators by tapping into unused capacity at the old incinerators. Also doesn't affect rhe conclusion whether increased use of incineration will lead to more toxic leaks.

Statement D

This statement strengthens the argument; which is the opposite of what we're aiming to achieve.

Statement E

This statement hints that the toxic leaks do not have that much of a harmful effect because the toxic releases do not go beyond the property of the incinerator. This also doesnt tackle the conclusion about the frequency of leaks, it only addresses how not harmful the toxic leaks can be.

Hope this Helps!!!

5 0
3 years ago
3.5 grams is equivalent to how many kilograms? 3500 kg 35,000 kg 0.35 kg 0.0035 kg
bagirrra123 [75]
There are 1000 grams in a kg.
To convert g to kg, dovide by 1000.

3.5/1000= 0.0035 kg

Final answer: D
4 0
3 years ago
An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu
chubhunter [2.5K]

Answer:

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

The density of a proton is 6.278\times 10^{14} g/cm^3.

Explanation:

Diameter of the atom ,d = 2.50 Å

Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\pi r^3..[1]

Diameter of the nucleus ,d' = 9.00\times 10^{-5}\AA

Radius of the nucleus ,r' = 0.5 d'=0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA

Volume of nucleus = V'

V=\frac{4}{3}\pi r'^3..[2]

Dividing [2] by [1]

\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}

=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}

\frac{V'}{V}=4.6656\times 10^{-14}

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

Diameter of the proton ,d = 1.72\times 10^{-15} m = 1.72\times 10^{-13} cm

1 m = 100 cm

Radius of the proton,r = 0.5 d=0.5\times 1.72\times 10^{-13} cm=8.6\times 10^{-14} cm

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3

Mass of proton, m = 1.0073 amu = 1.0073\times 1.66054\times 10^{-24} g

1 amu = 1.66054\times 10^{-24} g

Density of the proton : d

d=\frac{m}{V}=\frac{1.0073\times 1.66054\times 10^{-24} g}{2.664\times 10^{-39}cm^3}=6.278\times 10^{14} g/cm^3

The density of a proton is 6.278\times 10^{14} g/cm^3.

5 0
3 years ago
Look at pic and help
natita [175]

Answer:

Answer

Explanation:

1) Other gasses / or argon (based on what u took in ur school )

2) oxygen

3? Nitrogen

3 0
2 years ago
Read 2 more answers
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