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Margaret [11]
3 years ago
14

Which of the following pairs of elements could possibly be in the same group? X has a 1+ ion; Y has a 1- ion. X tends to form a

2+ ion; Y tends to gain two electrons. X will tend to gain one electron; Y has eight valence electrons. X has an atomic number 15; Y forms a 3- ion.
Chemistry
2 answers:
exis [7]3 years ago
5 0
Let's eliminate these one by one.
The first pair would not be the same, as X would most likely be in group IA, and Y would be in group VIIA, because of their tendency to gain and lose electrons.
The second pair would also violate the same rule, but X would most likely be in group IIA, and Y would most likely be in group VIA.
The third pair would not be the same, as X is most likely in group VIIA, and since Y has eight valence electrons, it is most likely a noble gas.
The final pair has X with atomic number 15, making it phosphorous. Phosphorous wants to gain 3 electrons to have a full octet of 8 outer "valence" electrons, and Y would also like to gain 3 electrons. This means it is possible that the final pair would be in the same group.
White raven [17]3 years ago
3 0

Answer is: X has an atomic number 15; Y forms a 3- ion.

1)  X has a 1+ ion; Y has a 1- ion is not correct, because X is probably metal (lost one electron, group 1) and Y is nonmetal (gain one electron, group 17).

2) X tends to form a 2+ ion; Y tends to gain two electrons is not correct, because X lost two electrons (probably metal from group 2).

3) X will tend to gain one electron; Y has eight valence electrons is not correct, because X is probably from group 17 and Y is noble gas (group 18).

4) Y is phosphorus (atomic number 15, group 15) and Y is nonmetal from group 15.

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Without wasting much of our time, Here is the correct question.

Hemoglobin molecules in blood bind oxygen and carry it to cells, where it takes part in metabolism. The binding of oxygen hemoglobin(aq) + O2(aq) -------> hemoglobin O2(aq) is first order in hemoglobin and first order in dissolved oxygen, with a rate constant of 4 × 10⁷ L mol⁻¹ s⁻¹. Calculate the initial rate at which oxygen will be bound to hemoglobin if the concentration of hemoglobin is 2 × 10⁻⁹ M and that of oxygen is 5 × 10⁻⁵M.

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The equation for the reaction between Hemoglobin molecules in blood that binds with oxygen molecule can be represent by:

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Now, we are also being told to calculate only!, the  initial rate at which oxygen will be bound to hemoglobin.

So, If it is first order in hemoglobin and also first order in Oxygen molecule at the initial rate of the the reaction, therefore, the rate  for the reaction can be expressed as :

rate = k [hemoglobin_{(aq)}][O_{2(aq)}]

Let's not forget that we are so given some parameters;

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Substituting our data given into the above rate formula, we have:

rate = (4 × 10⁷ L mol⁻¹ s⁻¹) × (2 × 10⁻⁹ M) × (5 × 10⁻⁵ M)

rate = 4 × 10⁻⁶ M s⁻¹     ( given that 1 M = 1 mol L⁻¹ )

∴ the initial rate at which oxygen will be bound to hemoglobin = 4 × 10⁻⁶ M s⁻¹

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