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stiv31 [10]
3 years ago
9

Jade(a green gemstone) has a density of 3.6g/ml. If a sample displaces 35.5mL of water, what is the jades's mass?

Chemistry
2 answers:
Sonja [21]3 years ago
7 0
Hey there!:

Mass =  ?

Volume = 35.5 mL

density = 3.6 g/mL 

By the definition of density :

D = m / V

3.6 = m / 35.5

m = 3.6 * 35.5

m = 127.8 g


hope this helps!
tatuchka [14]3 years ago
3 0

Answer is: mass of a green gemstone is 127.8 grams.

d(jade) = 3.6 g/mL; density of jade.

V(jade) = 35.5 mL; volume of jade.

m(jade) = d(jade) · V(jade).

m(jade) = 3.6 g/mL · 35.5 mL.

m(jade) = 127.8 g; mass.

Density is a measure of mass per unit of volume (in this example grams per milliliter).

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4 0
3 years ago
A cylindrical piece of metal is 4.5 dm in height with radius of 5.50 x 10^-5 km.
adell [148]

Answer:

a) V=4.3x10^3mL

b) V=4.3x10^6mm^3

c) \rho=1.5x10^5g/L

Explanation:

Hello,

a) In this case, the given height in cm is:

h=4.5dm*\frac{1m}{10dm}* \frac{100cm}{1m}=45cm

And the radius in cm is:

r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{100cm}{1m}=5.5cm

Thus, the volume in cubic centimeters which is also equal in mL (1cm³=mL) is:

V=\pi (5.5cm)^2*45cm\\\\V=4.3x10^3cm^3=4.3x10^3mL

b) In this case, the given height in mm is:

h=4.5dm*\frac{1m}{10dm}* \frac{1000mm}{1m}=450mm

And the radius in mm is:

r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{1000mm}{1m}=55mm

Thus, the volume in cubic millimeters is:

V=\pi (55mm)^2*450mm\\\\V=4.3x10^6mm^3

c) Finally, since 1000 mL equal 1 L, the required density in g/L turns out:

\rho=\frac{m}{V}=\frac{6.54x10^5g}{4.3x10^3mL}*\frac{1000mL}{1L}\\   \\\rho=1.5x10^5g/L

Best regards.

8 0
3 years ago
Please help meee 1st question​
spayn [35]
360 seconds?

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