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Nutka1998 [239]
3 years ago
10

A container holds 6.4 moles of gas. Hydrogen gas makes up 25% of the total moles in the container. If the total pressure is 1.24

atm. What is the partial pressure of hydrogen? Use mc032-1.jpg.
Chemistry
1 answer:
Degger [83]3 years ago
6 0
  The   partial  pressure of hydrogen is 0.31  atm

calculation

find the number of  hydrogen   moles the container, that is

25/100  x 6.4  =1.6 moles of hydrogen

find the  partial pressure for hydrogen  in 1.6 moles

that is   6.4  moles=  1.24 atm
            1.6  moles= ?

by  cross  multiplication

1.6moles  x1.24  atm/ 6.4 moles=  0.31 atm
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The answer is 14.22 mg / (mm^2)
6 0
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On the basis of dipole moments and/or hydrogen bonding, explain in a qualitative way the differences in the boiling points of ac
Inga [223]
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7 0
3 years ago
1. If you have 5g of pennies how many dozen pennies do you have?
likoan [24]

Answer:

15.69 dozen

Explanation:

Mass of penny = 5 g

Dozens of penny =..?

Next, we shall convert 5 g to gross. This can be obtained as follow:

3824 g = 1000 gross

Therefore,

5 g = 5 g × 1000 gross / 3824 g

5 g = 1.3075 gross

Thus, 5 g is equivalent to 1.3075 gross.

Finally, we convert 1.3075 gross to dozen. This can be obtained as follow:

1 gross = 12 dozen

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4 0
3 years ago
How would you prepare 3.5 L of a 0.9M solution of KCl?
Fudgin [204]
Calculate the mass of the solute <span>in the solution :

Molar mass KCl = </span><span>74.55 g/mol

m = Molarity * molar mass * volume

m = 0.9 * 74.55 * 3.5

m = 234.8325 g 

</span><span>To prepare 0.9 M KCl solution, weigh 234.8325 g of salt in an analytical balance, dissolve in a beaker, shortly after transfer with the help of a funnel of transfer to a volumetric flask of 100 cm</span>³<span> and complete with water up to the mark, then cover the balloon and finally shake the solution to mix

hope this helps!</span>
8 0
3 years ago
A sample has a pH of -0.248 (yes, it really is possible to have a negative pH). Find
dalvyx [7]

Answer:

pOH= 14.248

[H+]=1.77 M

[OH-]=5.65 x10^-15M

Explanation:

pH+pOH= 14

pOH= 14-pH

pOH=14-(-0.248)

pOH= 14.248

[H+]=10^-pH= 10^-(-0.248)=1.77 M

[OH-]=10^-pOH= 10^-14.248=5.65 x10^-15M

5 0
3 years ago
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