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AveGali [126]
3 years ago
13

Solve for h A=1/2(ah/bh)

Mathematics
1 answer:
masya89 [10]3 years ago
7 0

Answer the answer is in the attachment

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The hypotenuse of a 45°-45°-90° triangle measures 4 cm. What is the length of one leg of the triangle? 2 cm 2 StartRoot 2 EndRoo
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Answer:

2\sqrt{2} cm

Step-by-step explanation:

In order to solve this you just have to remember the formula for the sides and hypotenuse of the triangle rectangle:

c^{2} =a^{2} +b^{2}

Since A and B are equal we will use X to represent them both:

c^{2} =a^{2} +b^{2}\\4^{2} =x^{2} +x^{2}\\16 =2x^{2}\\8=x^{2} \\x=\sqrt{8}=\sqrt{4*2}=2\sqrt{2}

ANd by solving the equation we get that the length of the legs of the triangle rectangle with a hypotenuse of 4cm is 2\sqrt{2} cm

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