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natita [175]
3 years ago
11

What happens to the speed of light as it passes into a glass block?

Physics
2 answers:
Ksju [112]3 years ago
8 0
It slows down. The reason for this is because when the light travels through the air, it is at it’s maximum speed. When it passes through the glass block, it slows down because the medium is denser than air. This also causes refraction.
Deffense [45]3 years ago
7 0
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ The speed would reduce as glass is denser than air.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Four football players are running down the field at the same speed. Player 1 weighs 180 lbs and is running toward the south goal
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3 years ago
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A plane is landing. It started at 400m/s and ended up at 50m/s after 30 seconds. What is it's acceleration?
quester [9]

Give u = start velocity

        v = end velocity

v = u + at

50 = 400 + a*30

30a = -350

a = -116.67 m/s^{2}

**Why the accecleration is negative number**

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4 0
3 years ago
Name and describe the two layers inside Earth that are undergoing convection and indicate one major consequence of each.
Lilit [14]

Answer:

Mantle and core

Explanation:

The Mantle and Core are the two components within Earth experiencing convection. In several ways the mantle is significant. The one outcome of convective current is the creation of the fresh oceanic lithosphere around OCEANIC RIDGES, formed by mantle upwelling. Core is indeed the planet's innermost layer.

5 0
3 years ago
A 25.0 kg pickle is accelerated from rest through a distance of 6.0m in 4.0s across a level floor . If the friction force betwee
SIZIF [17.4K]
Add the KE increase and the work done against friction.

The final velocity is twice the average, or 3.0 m/s
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The friction work done is 6*3.8 = 22.8 J 
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8 0
4 years ago
If an electron moves in a circle of radius 21 cm perpendicular to a B field of 0.4 T, what are the speed of the electron and the
kodGreya [7K]

Answer:

a)

v = 4.048 *10^6 m/s

b)  

Angular frequency =  1.92 * 10^7

Explanation:

As we know

v =  \frac{qBr}{m}

q is the charge on the electron = 3.2 * 10^{-19} C

B is the magnetic field in Tesla = 0.4 T

r is the radius of the circle = 0.21 m

mass of the electrons = 6.64 * 10^{-27} Kg

a)

Substituting the given values in above equation, we get -

v = \frac{3.2 * 10^{-19}*0.4*0.21}{6.64 * 10^{-27}} \\v = 4.048 *10^6m/s

b)  

Angular frequency =

\frac{4.048 * 10^6 }{0.21} \\1.92 * 10^7

8 0
3 years ago
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