Question

A projectile is fired with an initial speed of 37.0 m/s at an angle of 43.7 ∘ above the horizontal on a long flat firing range. What is the maximum height.

Answer 1

Answer:

The maximum height reached by the projectile is 33.34 m

Explanation:

Given;

initial velocity of the projectile, u = 37 m/s

angle of projection, θ = 43.7°

The maximum height reached by the projectile = ?

Apply the following kinematic equation, to determine the maximum height reached by the projectile.

Maximum height (H) is given as;

$H = \frac{u^2 sin^2\theta}{2g}\\\\ H = \frac{(37)^2 (sin 43.7)^2}{2*9.8}\\\\H = 33.34 \ m$

Therefore, the maximum height reached by the projectile is 33.34 m