Answer:
The maximum height reached by the projectile is 33.34 m
Explanation:
Given;
initial velocity of the projectile, u = 37 m/s
angle of projection, θ = 43.7°
The maximum height reached by the projectile = ?
Apply the following kinematic equation, to determine the maximum height reached by the projectile.
Maximum height (H) is given as;
Therefore, the maximum height reached by the projectile is 33.34 m
Answer:
15.19°, 31.61°, 51.84°
Explanation:
We need to fin the angle for m=1,2,3
We know that the expression for wavelenght is,
Substituting,
Once we have the wavelenght we can find the angle by the equation of the single slit difraction,
Where,
W is the width
m is the integer
the wavelenght
Re-arrange the expression,
For m=1,
For m=2,
For m=3,
<em>The angle of diffraction is directly proportional to the size of the wavelength.</em>
When acceleration is constant, the average velocity is given by
where and
are the final and initial velocities, respectively. By definition, we also have that the average velocity is given by
where are the final/initial displacements, and
are the final/initial times, respectively.
Take the car's starting position to be at . Then
So we have
You also could have first found the acceleration using the equation
then solve for via
but that would have involved a bit more work, and it turns out we didn't need to know the precise value of anyway.
Answer:
λ = 482.05 nm
Explanation:
The diffraction phenomenon and the diffraction grating is described by the expression
d sin θ = m λ
where d is the distance between two consecutive slits, λ the wavelength and m an integer representing the order of diffraction
in this case they indicate the distance between slits, the angle and the order of diffraction
λ = d sin θ / m
let's calculate
λ = 1.00 10⁻⁶ sin 74.6 / 2
λ = 4.82048 10⁻⁷ m
Let's reduce to nm
λ = 4.82048 10⁻⁷ m (10⁹ nm / 1 m)
λ = 482.05 nm