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Flura [38]
3 years ago
6

The "big bang" refers to the origin of:

Physics
1 answer:
polet [3.4K]3 years ago
7 0
The answer is E. Our Universe
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An object is pulled northward at 20 N and southward at 15 N. What is the direction and force of the object?
Elden [556K]

Answer:

It moves northward at 5N

Explanation:

5 0
3 years ago
If a lever is 10m long and the effort is applied 4m from the fulcrum, what is the MA of the lever?
Marizza181 [45]
We Know: MA = d₁ / d₂
Here, d₁ = 4
d₂ = 10-4 = 6

Substitute their values into the expression:
MA = 4/6
MA = 2/3

So, Your Answer would be 2/3


Hope this helps!
3 0
3 years ago
Transfer of heat through conduction can occur in which of the following?
lianna [129]

Answer:d I think

Explanation:

8 0
3 years ago
Read 2 more answers
Use Percentages Given that the molecular mass of magnesium
ira [324]

Answer:

27%

Explanation:

15.999 divided by 58.32 = .27433128

Move the decimal place over 2 places.

27%

5 0
4 years ago
Based on the data collected, explain why a launch angle of 30 degrees (HIGH HORIZONTAL VELOCITY & SMALL TIME OF FLIGHT) will
Gennadij [26K]

Answer:

Explanation:

The horizontal distance traveled by the projectile is given by the formula

R=\frac{u^{2}Sin2\theta }{g}

The formula for the time of flight is given by

T = \frac{2u Sin\theta }{g}

Case I: when the launch angle is 30°

So, R_{1}=\frac{u^{2}Sin60 }{g}

R_{1}=\frac{0.866u^{2}}{g}

Horizontal velocity = u Cos 30 = 0.866 u

T_{1} = \frac{2u Sin30 }{g}=\frac{u}{g}

Case II: when the launch angle is 60°

R_{2}=\frac{u^{2}Sin120}{g}

R_{2}=\frac{0.866u^{2}}{g}

Horizontal velocity = u Cos 60 = 0.5 u

T_{1} = \frac{2u Sin60 }{g}=\frac{1.73 u}{g}

By observing the case I and case II, we conclude that

R1 = R2

Horizontal velocity 1 > Horizontal velocity 2

T1 < T2

5 0
3 years ago
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