Answer:
60 grams of ice will require 30.26 calories to raise the temperature 1°C.
Explanation:
The amount of heat (Q) to raise the temperature of 60.0 g of ice by 1°C can be calculated from:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat released or absorbed by the system.
m is the mass of the ice (m = 60.0 g).
c is the specific heat capacity of ice (c = 2.108 J/g.°C).
ΔT is the temperature difference (ΔT = 1.0 °C).
∴ Q = m.c.ΔT = (60.0 g)(2.108 J/g.°C)(1.0 °C) = 126.48 J.
<em>It is known that 1.0 cal = 4.18 J.</em>
<em>∴ Q = (126.48 J)(1.0 cal / 4.18 J) = 30.26 cal.</em>
Answer:
Equilibrium is the state of balance. Where opposing forces cancel each other out and no changes are occurring.
<em>Good luck, hope this helps :)</em>
a is the answer because all of the other answers are wrtong
Answer:
suspension
Explanation:
a mixture in which particles can be seen and easily separated by settling or filtration.
hope this helps
Solve the following equation and check for extraneous solutions. Show all work. Thank you.
sqrt(sqrt(x - 3)) = sqrt(x - 15)
