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castortr0y [4]
3 years ago
14

PLEASE HELP I GIVE BRAINLIEST

Chemistry
1 answer:
antiseptic1488 [7]3 years ago
6 0
I would say that it's C. Seasonal temperatures have dipped over time, but I could easily be wrong, since it's my opinion. A weather condition is defined as the atmospheric conditions that 'comprise the state of the atmosphere in terms of temperature and wind and clouds and precipitation. But I believe it could just as easily be B. 150mm of rainfall is a normal average in the city.
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In order to keep the bench from conducting heat, Shane could build it out of _______.
lara31 [8.8K]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ In order to keep the bench from conducting heat, Shane could build it out of wood. Wood doesn't conduct heat so this would work best for Shane.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

8 0
4 years ago
Read 2 more answers
How would you know if this combination is likely to be found in dirt? Please explain!
Elan Coil [88]
No it is not likely. That is a ratio of 10:4 N^14 and N^15 which doesn’t work. It needs a higher amount
4 0
3 years ago
Read 2 more answers
A football field is 120 yards by 53.333 yards. What is the area of the football field in acres if 1 acre=43560 ft?? Use correct
maw [93]

Answer:

1.3223 acres

Explanation:

a football field's area is 360 feet (120 yards) x 160 feet (53.333 yards) = 57,600 sq. feet

if the area of an acre is 43,560 sq. feet, then a football field in acres = 57,600 sq. feet / 43,560 sq. feet = 1.3223 acres

we can verify our answer by doing the same calculation in sq. yards:

football field = 120 yards x 53.33 yards = 6,400 sq. yards

an acre is 4,840 sq. yards

football field in acres = 6,400 sq. yards / 4,840 sq. yards = 1.3223 acres

8 0
3 years ago
Read 2 more answers
Cal is titrating 50.8 mL of 0.319 M HBr with 0.337 M Ba(OH)2. How many mL of Ba(OH)2 does Cal need to add to reach the equivalen
alexgriva [62]

Answer:

V_{base}=24.04mL

Explanation:

Hello!

In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

2HBr+Ba(OH)_2\rightarrow BaBr_2+2H_2O

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

2M_{base}V_{base}=M_{acid}V_{acid}

Therefore, for is to compute the volume of the used base, we proceed as shown below:

V_{base}=\frac{M_{acid}V_{acid}}{2M_{base}}

And we plug in to obtain:

V_{base}=\frac{0.319M*50.8mL}{2*0.337M}\\\\V_{base}=24.04mL

Best regards!

8 0
3 years ago
In today's experiment, Solutions A and B are prepared as follows.
hram777 [196]

Answer:

D. 0.160

Explanation:

The solution A is obtained adding 2.0mL of a solution of bromocresol green, 5.0mL of 1.60M HAc and 2.0mL of a solution of KCl. The solution is diluted to 50mL

That means the HAc is diluted from 5.0mL to 50.0mL, that is:

50.0mL / 5.0mL = 10 times.

And the final concentration of HAc must be:

1.60M / 10 times =

0.160M

Right answer is:

<h3>D. 0.160</h3>
3 0
3 years ago
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