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vagabundo [1.1K]
3 years ago
5

What type of reaction is this? 2 A1203 (s) + 4 Al(s) + 3 O2 (g)

Chemistry
1 answer:
GaryK [48]3 years ago
7 0

Answer:

Decomposition

Explanation:

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What is one way that electric charges are different from magnetic poles?
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The answer is A. As the first statement is a true statement. Hope this help you
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In aqueous solution, hypobromite ion, BrO-, reacts to produce bromate ion, BrO3 -, and bromide ion, Br-, according to the follow
maw [93]

Answer:

22.73s

Explanation:

The reaction is a second order reaction, we know this by observing the unit of the slope.

rate constant = k = 0.056 M-1s-1

the initial concentration of BrO- [A]o = 0.80 M

time = ?

Final concentration [A]t= one-half of 0.80 M = 0.40M

1 / [A]t = kt + 1 / [A]o

1 / 0.40 = 0.056 * t + 1 / 0.80

t = (2.5 - 1.25) / 0.056

t = 22.73s

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3 years ago
In the unbalanced equation given below, what is the element that is gaining electrons?
viktelen [127]

Hey there!:

HCl + MnO2 → MnCl2 + H2O + Cl2

* in HCl the oxidation state of Cl is -1 .

* on the product side the oxidation state is 0 .

* therefore Cl gains electrons .

* in  MnO2 the oxidation state of Mn is +4

* in MnCl2 the oxidation state of Mn is +2

Therefore Mn loses electrons

Answer A

Hope That helps!

4 0
3 years ago
Read 2 more answers
Write the acid-base reaction that occurs when an aqueous solution of HCl is added to an aqueous solution of NaOH. (Use the lowes
Sloan [31]
H3O+(aq) + OH-(aq) --> 2H2O (l)

NaHCO3(s) --> NaH 2+ (aq) + CO3 2- (aq)

NaH 2+ (aq) + H2O (l) --> Na+ (aq) + H3O+ (aq)

H2O (l) + CO3 2- (aq) --> OH- (aq) + HCO3- (aq)

(I'm not completely sure if I did the third question right) I'm sorry if I got it wrong
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3 years ago
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Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
galina1969 [7]

Answer:

\%\, yield\, \, SO_3=82.29

Explanation:

First write the balance eqation of chemical reaction:

2S(s) +3O_2(g) \rightarrow 2SO_3(g)

Remember writing any chemical reaction from its  elemetal form then write the elements in their natural form i.e. how that element exists in the nature here sulphur exists in solid monoatomic form in the nature and oxygen in gaseous diatomic form.

mass of oxygen given=5gram

mole of oxygen=5/32mol=0.16mol

mass of sulpher given=6gram

mole of sulpher=6/32mol=0.19mol

from the above balanced equaion;

2 mole of sulphur reacts with 3 mole Oxygen completely

1 mole of sulphur reacts with 1.5 mole Oxygen completely

0.19 mole of sulphur reacts with 1.5\times 0.19 i.e. 0.285 mole Oxygen completely.

but we have 0.16 mole so oxygen will be the limiting reagent and sulpher will be the excess reagent

so product will depend on the limiting reagent

from the balance equation

3 mole of sulpher gives 2 mole SO_3

1 mole of sulpher will give 2/3 mole SO_3

0.16 of sulpher will give 0.12 mole SO_3

mass of SO_3=9.6gram this is theoreical production of SO_3

and

actual production of SO_3 =7.9gram

\%\, yield   \,\, SO_3=\frac{Actual \,yield}{theoretical\, yield}\times 100

\%\, yield\, \, SO_3=\frac{7.9}{9.6} \times 100=82.29

\%\, yield\, \, SO_3=82.29

3 0
3 years ago
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