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3 years ago

PLEASE PLEASE PLEASE HELPPP

Chemistry

1 answer:

Ivan3 years ago

8 0

I believe that the answer is B

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A compound is found to contain 42.88 % carbon and 57.12 % oxygen by weight. To answer the questions, enter the elements in the o

Ipatiy [6.2K]

Answer:

The empirical formule is CO

Explanation:

Step 1: Data given

Suppose the mass of a compound is 100 grams

Suppose the compound contains:

42.88 % C = 42.88 grams C

57.12 % O = 57.12 grams O

Molar mass C = 12.01 g/mol

Molar mass O = 16.0 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles C = mass C / molar mass C

Moles C = 42.88 grams / 12.01 g/mol

Moles C = 3.57 moles

Moles O = 57.12 grams / 16.0 g/mol

Moles O = 3.57 moles

Step 3: Calculate the mol ratio

We divide by the smallest amount of moles

C: 3.57 moles / 3.57 moles = 1

O: 3.57 moles / 3.57 moles = 1

The empirical formule is CO

3 0

2 years ago

Why did rutherford conclude from his gold foil experiment that an atom is mostly comprised of empty space?

Nady [450]

'cause many alpha-particle goes without any deflection........

6 0

3 years ago

The ion MnOis often used to analyze for the Fe2+ content of an aqueous solution by using the (unbalanced) reaction Mno+Fe2+ + Fe

dusya [7]

Answer:

B) 0.230 M

Explanation:

The first step is to balance the reaction between the Ferrous ion and the permanganate ion:

$5~Fe^+^2~+~MnO_4^-^1~+~8H^+~->~5Fe^+^3~+~Mn^+^2~+4H_2O$

Then we have to calculate the moles of $MnO_4^-$ :

$M~=~\frac{mol}{L}$

$mol~=~M*L$

$mol~=~0.033~M*0.0633L=~0.002088~mol~MnO_4^-$

Then using the molar ratio we can find the moles of $Fe^+^2$ :

$0.002088~mol~MnO_4^-\frac{5~mol~Fe^+^2}{1~mol~MnO_4^-}=0.01044~mol~Fe^+^2$

Finally we can calculate the molarity:

$M=\frac{0.01044~mol~Fe^+^2}{0.0455~L}=0.230~M$

5 0

3 years ago

A buret was improperly read to 1 decimal place giving a reading of 27.2 mL. If the actual volume is 27.26 mL, what is the percen

Nezavi [6.7K]

Percent error can be calculated by the difference of the theoretical value and the measured value divided by the theoretical value multiplied by 100 percent.

% error = 27.26 - 27.2 / 27.26 x100
% error = 0.22%

A value close to zero would mean that the measured value is more or less near the actual value.

5 0

2 years ago

Read 2 more answers

What is the percent by mass of water in Na2SO4 • 10H2O?

bulgar [2K]

We determine the percent by mass of water in the compound by dividing the mass of water by the total mass. The total mass of Na2SO4.10H2O is equal to 322 g. The mass of water is 180 g.

percent by mass of water = (180 / 322)*(100 %) = 55.9%

5 0

3 years ago

Read 2 more answers