Answer:
The answer to your question is 1) 0.037 M 2) 0.32 M 3) 0.096 M
Explanation:
a) 125 ml of 0.251 M HCl
-Calculate the moles of HCl
Molarity = moles/volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = 0.251 x 0.125
= 0.0314
-Calculate the new molarity
Molarity = 0.0314/ (0.125 + 0.250)
-Simplification
Molarity = 0.014/0.375
-Result
Molarity = 0.037 M
2.-
445 ml of 0.499 M of H₂SO₄
-Calculate the number of moles
moles = 0.499 x 0.445
moles = 0.222
-Calculate the new molarity
Molarity = 0.222/(0.445 + 0.25)
Molarity = 0.222/0.695
Molarity = 0.32
3)
5.25 l of HCO₃ 0.101 M
Calculate the number of moles
moles = 0.101 x 5.25
moles = 0.53
-Calculate the Molarity
Molarity = 0.53 / (0.25 + 5.25)
Molarity = 0.53 / 5.5
Molarity = 0.096
Answer:
2.3 M
Explanation:
First we calculate the final volume of the solution:
- Final Volume = 200 mL + 700 mL
With the final volume we can use a <em>dilution factor</em> to c<u>alculate the concentration of the diluted solution</u>:
- Original Concentration * Initial Volume / Final Volume = Final Concentration
- 3 M * 700 mL / 900 mL = 2.3 M
Steroids are lipids and complex carbohydrates
Answer: C. Gas particles move faster and farther apart at higher temperatures.
Explanation:
The options include:
A. the number of gas particles increases at higher temperatures
B. the number of gas particles decreases at higher temperatures
C. gas particles move faster and farther apart at higher temperatures
D. gas particles move more slowly and get closer together at higher temperatures
The statement that describes how the outcome (dependent) variable changes as a result of the changes made to the tested (independent) variable is that gas particles move faster and farther apart at higher temperatures.
It should be noted that the particles in the gases will collide more frequently with one another because of the shorter space that is between them.
The increase in the temperature will bring about a faster movement of the particles which in turn, brings about a rise in the diffusion rate and also the collision rate.
