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OverLord2011 [107]
4 years ago
14

There are 336 students in a college who have taken a course in calculus, 227 who have take a course in discrete mathematics, and

171 who have taken a course in both calculus and discrete mathematics. How many students at this college have taken a course in either calculus or discrete mathematics?
Mathematics
1 answer:
Nataliya [291]4 years ago
6 0

Answer: 392

Step-by-step explanation:

Le A denotes the number of students takes calculus .

and B denotes the number of students takes discrete mathematics .

Given: There are 336 students in a college who have taken a course in calculus, 227 who have take a course in discrete mathematics, and 171 who have taken a course in both calculus and discrete mathematics.

i.e. n(A)= 336  ,  n(B)=227

and n(A and B)=n(A∩B) =171

Using formula : n(A∪B)=n(A)+n(B)+n(A∩B)

⇒ n(A∪B)=336+227-171=392

Hence, the  number of students at this college have taken a course in either calculus or discrete mathematics = 392

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