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Ierofanga [76]
3 years ago
6

Stephen was helping make party bags for his little brother’s party. They have to make a total of 10 party bags. They had 34 toy

cars to place in the party bags and want to make sure each child received the same number of toy cars. How many cars did each child receive? What does the remainder mean in this problem?
A) Each child will receive 3 cars and 4 cars will be left over.
B) Each child will receive 4 cars and 3 cars will be left over.
C) Each child will receive 3 cars and no cars will be left over.
D) Each child will receive 4 cars and no cars will be left over.
Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0
A) Each child will receive 3 cars and 4 cars will be left over.
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Svet_ta [14]

The answer should be B bc the point is at 1 and it rises 2 and runs 3 to the left so it’s negative
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3 years ago
Last year there were 145 pies baked for the bake sale this year k pies baked using k write a expression for the total number of
allsm [11]

Answer:

The number of pies baked in the two years = ( k + 145) pies

Step-by-step explanation:

Here, we are interested in writing an expression for the total number of pies baked in the two years.

Last year, the number of pies baked = 145

This year the number of pies baked = k

Thus, the total number of pies baked in the two years will be ( k + 145) pies

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3 years ago
When multiplying and dividing two numbers in scientific notation, why do u sometimes have to rewrite one factor ?
zalisa [80]

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2x10^3 * 5x10^9

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3 years ago
Read 2 more answers
Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe
solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for p such that 1000p(1-p) is maximized. Once we have that p, we can easily find the answer to part b.

Finding the value that maximizes 1000p(1-p) is the same as finding the value that maximizes p(1-p), just on a smaller scale. So, we really want to maximize p(1-p). To do this, we will do a trick called completing the square.

p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4.

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of p such that the inner part of the square term is equal to 0.

p-1/2=0\\p=1/2.

So, the answer to part a is \boxed{1/2}.

We can then plug 1/2 into the equation for p to find the answer to part b.

1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250.

So, the answer to part b is \boxed{250}.

And we're done!

3 0
3 years ago
If a/2b =3/5 and 4b/3c=1/7, then a/c=<br> I will mark you brainlist whoever get this correct
ioda

Answer:

a/c=2/7 u are welcome thanks for ur help

7 0
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