The largest numbers of snacks bag can be number 80 which consists of 24 jolly ranchers and 56 blow pops.
Given that Rashad has 24 jolly ranchers and 56 blow pops for making treat bags for his sister's birthday party and asked to find out the largest numbers of snacks in the bag.
There are 24 jolly ranchers and 56 blow pops and For the maximum numbers of snacks in the bag can be 24 jolly ranchers and 56 blow pops.
The maximum numbers of snacks that can be filled in a snacks bag is 24 jolly ranchers and 56 blow pops.
Therefore,The largest numbers of snacks bag can be number 80 which consists of 24 jolly ranchers and 56 blow pops.
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Answer:
12
Step-by-step explanation:
Answer
z= 14
Step-by-step explanation:
4( 2z-3) -5(z-6) =3 *20
8z-12-5z+30=60
3z+18=60
3z=60-18
3z=42
z= 14
Answer:
I dont under stand sorry :(
Step-by-step explanation:
Recursive
formula is one way of solving an arithmetic sequence. It contains the initial
term of a sequence and the implementing rule that serve as a pattern in finding
the next terms. In the
problem given, the 6th term is provided, therefore we can solve for the initial
term in reverse. To make use of it, instead of multiplying 1.025, we should divide it after
deducting 50 (which supposedly is added).
<span>
Therefore, we perform the given formula: A (n) = <span>1.025(an-1) +
50
</span></span>a(5) =1.025 (235.62) + 50 = 291.51
a(4) = 1.025 (181.09) + 50 = 235.62
a(3) = 1.025 (127.89) + 50 = 181.09
a(2) = 1.025 (75.99) + 50 = 127.89
a(1) = 1.025 (25.36) + 50 = 75.99
a(n) = 25.36
The terms before a(6) are indicated above, since a(6) is already given.
So, the correct answer is <span>
A. $25.36, $75.99.</span>
