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1 year ago

This is a Math question.

1 answer:

7 0

A figure can be graphed on a coordinate plane as a set of points located on specific places, specified by their coordinates.

<h3>How to draw graph on cartesian coordinate plane?</h3>

The cartesian coordinate plane is an infinite 2 dimensional plane and each point of a cartesian plane is tracked by a location.

Now, the perpendicular distance of point from the horizontal axis and vertical axis are respectively usually named x-axis and y-axis. The location is then written as (a,b) where;

a is that point's shortest distance from the y-axis and called x-coordinate of that point.

b is that point's shortest distance from the x-axis, and called y-coordinate of that point.

Thus, those given geometric figures can be graphed on a coordinate plane as a set of points located on specific places, specified by their coordinates.

Read more about cartesian Coordinates at; brainly.com/question/2141683

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Find the height of when's, 14,494. Round the height to the nearest thousand feet

8_murik_8 [283]

14,494
To round off the height value to the nearest thousand we can use the expanded from to clarity the position of numbers which is:
10, 000 = ten thousand
4, 000 = thousands
400 = hundreds
90 = tens
4 = ones
Here we can notice than four thousand is the value where the nearest thousands is placed. Hence we can round off the number of 14, 494 into 14, 000. Notice 0-4 rounding off rules.

8 0

3 years ago

What is the area of triangle ABC Round to the nearest tenth of a square unit

Inga [223]

Where’s the triangle, isn’t there supposed to be a picture with the question

5 0

3 years ago

Integral Calculation

Tatiana [17]

Answer:

$\frac{4}{3(e^2+1)}$

Step-by-step explanation:

We want to evaluate:

$\int\limits^1_{-1} {\frac{x^2+1}{e^2+1} } \, dx$

This is the same as:

$\frac{2}{e^2+1} \int\limits^1_{0} {x^2+1} \, dx$

We integrate to obtain:

$\frac{2}{e^2+1} (\frac{x^3}{3}+x)|_0^1$

We evaluate to obtain:

$\frac{2}{e^2+1} (\frac{1^3}{3}+1)=\frac{4}{3(e^2+1)}$

8 0

3 years ago

(hg^(-3))/(w^(-4) k^0 )

Svetlanka [38]

One may note you never quite asked anything, now, assuming simplification,

$\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{hg^{-3}}{w^{-4}k^0}\implies \cfrac{hw^4}{g^3(1)}\implies \cfrac{hw^4}{g^3}$

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2 years ago

Seraphina is driving two hours to visit her family. For the first hour, she traveled at a speed of 62 miles per hour. Then, in t

Murljashka [212]

Answer:

11.3%

Step-by-step explanation:

$\%\ increase=\frac{final-initial}{initial} \times 100\%\\\%\ increase=\frac{69-62}{62} \times 100\%\\\%\ increase=\frac{7}{62} \times 100\%\\\%\ increase=11.3\%$

6 0

3 years ago