Answer:
The surface area of the gift box that Kira decorates is ![253.5\ in^{2}](https://tex.z-dn.net/?f=253.5%5C%20in%5E%7B2%7D)
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
A cube has six square faces
The surface area of a cube is equal to the area of the six squares faces
![SA=6b^{2}](https://tex.z-dn.net/?f=SA%3D6b%5E%7B2%7D)
where
b is the length side of a cube
In this problem we have
![b=6.5\ in](https://tex.z-dn.net/?f=b%3D6.5%5C%20in)
substitute
![SA=6(6.5)^{2}](https://tex.z-dn.net/?f=SA%3D6%286.5%29%5E%7B2%7D)
![SA=253.5\ in^{2}](https://tex.z-dn.net/?f=SA%3D253.5%5C%20in%5E%7B2%7D)
This is something I’ve never seen before I think you have to add the numbers.
1. You are given PR and RS, so simply add the two measurements to get PS.
28.2+30.7= 58.9
2. Subtract QV from QT to get TV.
78-56= 22
3. Again, Subtract QV from QT to get TV.
74-36= 38
4. Similar to question 1, add PR and RS to get PS.
40+53= 93
Perpendicular lines, when intersecting, will always create a right angle at the intersection point. A right angle is an angle that is exactly 90 degrees.
The answer should be answer A. (A,C,D,K)
You can easily figure this out by just looking at the graph. Just look at all points that are in the blue region(overlapping shaded area) and see all the points inside.
H is not included because it falls on the dotted line. Any point that falls on a dotted line does not satisfy both inequalities.
If the line were solid however, then the point would satisfy both inequalities. This is because the line would include the <em>greater than or equal to</em> symbol "≥" which means that the point <em>could</em> equal to 8 or be less than 8. Since the symbol is not used, it doesn't satisfy both equations.