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SCORPION-xisa [38]
3 years ago
15

A hockey puck is pushed by a stick with a force of 750 newtons. The puck travels 2.0 meters in 0.30 seconds. How powerful is the

push? (Ignore frictional effects.)
Physics
1 answer:
myrzilka [38]3 years ago
7 0
The work done by the stick on the hockey puck is equal to the magnitude of the force times the distance covered by the puck:
W=Fd=(750 N)(2.0 m)=1500 J

And the power of the stick is equal to the ratio between the work done and the time taken, therefore
P= \frac{W}{t}= \frac{1500 J}{0.30 s}=5000 W
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What must be done to the wires used to make an electromagnet before they are connected​
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Neatly wrap the wire around the nail

Explanation:

hope this helps ( not sure tho )

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3 years ago
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2 (a) A plane from airport A flies 280 km to the east to airport B. The plane then travelled north to airport C, 190 km away. (i
Sonbull [250]

Answer:

See below

Explanation:

280 km   east then 190 km north

Use Pythagorean theorem to find the resultant displacement

d^2 = 280^2 + 190^2

d = 338.4 km

Angle will be    arctan ( 190/280) = 34.16 °

8 0
2 years ago
A positive charge is placed at rest at the center of a region of space in which there is a uniform electric field. (A uniform fi
Harlamova29_29 [7]

Answer:

.D.It will decrease because the charge will move in the direction of the electric field

Explanation:

<em>which there is a uniform electric field. (A uniform field is one whose strength and direction are the same at all points within the region.) What happens to the electric potential energy of the positive charge, after the charge is released from rest in the uniform electric field?A. It will remain constant because the electric field is uniform.B.It will decrease because the charge will move in the opposite direction of the electric field.C.It will remain constant because the charge remains at rest.D.It will decrease because the charge will move in the direction of the electric field.E.It will increase because the charge will move in the direction of the electric field.</em>

solution

The potential energy decreases, converted to kinetic energy

The charge will feel a force in the direction of the electric field (F=Eq) and thus it will accelerate with

a constant acceleration. (Just like releasing an object above the earth's surface - constant acceleration,

at least until it hits something.)

tus te answer will be

.D.It will decrease because the charge will move in the direction of the electric field

7 0
3 years ago
An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its l
Murrr4er [49]

Answer:

v = 25.45 m/s

Explanation:

In order to calculate the initial speed of the object, you take into account the formula for the maximum height reaches by the object. Such a formula is given by:

h_{max}=\frac{v_o^2}{g}   (1)

vo: initial speed of the object = 18 m/s

g: gravitational acceleration = 9.8 m/s²

Furthermore you use the following formula for the final speed of the object:

v^2=v_o^2-2gh       (2)

h: height

You know that the speed of the object is 18m/s when it reaches one fourth of the maximum height. You use this information, and you replace the equation (1) in to the equation (2), as follow:

v^2=v_o^2-2g(\frac{h_{max}}{4})=v_o^2-\frac{1}{2}g(\frac{v_o^2}{g})\\\\v^2=v_o^2-\frac{1}{2}v_o^2=\frac{1}{2}v_o^2

Then, you solve the previous result for vo:

v_o=\sqrt{2}v=\sqrt{2}(18m/s)=25.45\frac{m}{s}

The initial speed of the object was 25.45 m/s

3 0
3 years ago
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