health conditions and diseases
Answer:
Neatly wrap the wire around the nail
Explanation:
hope this helps ( not sure tho )
Answer:
See below
Explanation:
280 km east then 190 km north
Use Pythagorean theorem to find the resultant displacement
d^2 = 280^2 + 190^2
d = 338.4 km
Angle will be arctan ( 190/280) = 34.16 °
Answer:
.D.It will decrease because the charge will move in the direction of the electric field
Explanation:
<em>which there is a uniform electric field. (A uniform field is one whose strength and direction are the same at all points within the region.) What happens to the electric potential energy of the positive charge, after the charge is released from rest in the uniform electric field?A. It will remain constant because the electric field is uniform.B.It will decrease because the charge will move in the opposite direction of the electric field.C.It will remain constant because the charge remains at rest.D.It will decrease because the charge will move in the direction of the electric field.E.It will increase because the charge will move in the direction of the electric field.</em>
solution
The potential energy decreases, converted to kinetic energy
The charge will feel a force in the direction of the electric field (F=Eq) and thus it will accelerate with
a constant acceleration. (Just like releasing an object above the earth's surface - constant acceleration,
at least until it hits something.)
tus te answer will be
.D.It will decrease because the charge will move in the direction of the electric field
Answer:
v = 25.45 m/s
Explanation:
In order to calculate the initial speed of the object, you take into account the formula for the maximum height reaches by the object. Such a formula is given by:
(1)
vo: initial speed of the object = 18 m/s
g: gravitational acceleration = 9.8 m/s²
Furthermore you use the following formula for the final speed of the object:
(2)
h: height
You know that the speed of the object is 18m/s when it reaches one fourth of the maximum height. You use this information, and you replace the equation (1) in to the equation (2), as follow:

Then, you solve the previous result for vo:

The initial speed of the object was 25.45 m/s