The answer is A
Explanation:
Vacuuming doesn’t involve a lot of physical movements.
Answer:
- The emf of the generator is 6V
- The internal resistance of the generator is 1 Ω
Explanation:
Given;
terminal voltage, V = 5.7 V, when the current, I = 0.3 A
terminal voltage, V = 5.1 V, when the current, I = 0.9 A
The emf of the generator is calculated as;
E = V + Ir
where;
E is the emf of the generator
r is the internal resistance
First case:
E = 5.7 + 0.3r -------- (1)
Second case:
E = 5.1 + 0.9r -------- (2)
Since the emf E, is constant in both equations, we will have the following;
5.1 + 0.9r = 5.7 + 0.3r
collect similar terms together;
0.9r - 0.3r = 5.7 - 5.1
0.6r = 0.6
r = 0.6/0.6
r = 1 Ω
Now, determine the emf of the generator;
E = V + Ir
E = 5.1 + 0.9x1
E = 5.1 + 0.9
E = 6 V
Answer:
The smallest integer is n = 4
Explanation:
Using the equation V= Sqrt(F/Linear density)
V= Sqrt(341/0.0120)
V= Sqrt(28416.7)
V= 168.57m/s
Path distance =[ (n +1)/2]lambda
But V= f(Lambda)
n lambda/2 =L
n = f2L/V
n = (20 × 2 × 16.86) / 168.57
n = 4.0007
The smallest integer is n= 4
Answer:
Number of photons travel through pin hole=
Explanation:
First we will calculate the energy of single photon using below formula:
Where :
h is plank's constant with value 
c is the speed of light whch is
λ is the wave length = 532nm
E=
J
Number of photons emitted per second:
Number of photons emitted per second=
=
Where:
A-hole is area of hole
A-beam is area of beam
d-hole is diameter of hole
d-beam is diameter if beam
=
=
=
Number of photons travel through pin hole=
Number of photons travel through pin hole=
