Charcoal~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Answer;
= 312 Newtons
Explanation;
The bullet has a mass of 0.005 kg, and a velocity of 320 m/s, so we need to find it's final kinetic energy.
KE = 1/2*m*v^2
= 1/2*0.005*320^2
= 256 Joules.
Divide this by the distance over which this energy was received and you have the force that provided that energy.
= 256/0.820 = 312.195 Newtons
Rounded off, this is 312 N
Answer:
a) A = 0.603 m
, b) a = 165.8 m / s²
, c) F = 331.7 N
Explanation:
For this exercise we use the law of conservation of energy
Starting point before touching the spring
Em₀ = K = ½ m v²
End Point with fully compressed spring
= 
= ½ k x²
Emo =
½ m v² = ½ k x²
x = √(m / k) v
x = √ (2.00 / 550) 10.0
x = 0.603 m
This is the maximum compression corresponding to the range of motion
A = 0.603 m
b) Let's write Newton's second law at the point of maximum compression
F = m a
k x = ma
a = k / m x
a = 550 / 2.00 0.603
a = 165.8 m / s²
With direction to the right (positive)
c) The value of the elastic force, let's calculate
F = k x
F = 550 0.603
F = 331.65 N
Answer: Energy is released by the electron in the form of light
Explanation:
Let's start by explaining that each atom in its natural state has a specific structure of its energy levels. Where <u>the lowest energy level is called the </u><u>ground state</u><u>. </u>
<u>
</u>
So, when an atom is in its ground state, its electrons fill the lower energy orbitals completely before they begin to occupy higher energy orbitals.
Then, when an atom is excited, it means that it has left its ground state (in which each electron occupies its place in its orbit, around the nucleus), when this happens some electron jumps out of the orbit it occupied in its fundamental state to an outer orbit, further away from the nucleus <u>and then return to the ground state, emitting in the form of light the energy received.</u>
To understand it better:
An excited electron is an unstable electron, and when passing from one orbit to another, it produces light of a specific wavelength (color) that depends on the amount of energy the electron loses.
