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2 years ago

What is another element that will have the same valence electrons as Be and Ca?

Chemistry

1 answer:

Oduvanchick [21]2 years ago

8 0

Another element maybe BeCa if you combine them

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Use the provided reduction potentials to calculate ArGº for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu

nydimaria [60]

Answer : The correct option is, +91 kJ/mole

Solution :

The balanced cell reaction will be,

$Cu(s)+Pb^{2+}(aq)\rightarrow Cu^{2+}(aq)+Pb(s)$

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.

First we have to calculate the standard electrode potential of the cell.

$E^0_{[Pb^{2+}/Pb]}=-0.13V$

$E^0_{[Cu^{2+}/Cu]}=+0.34V$

$E^0_{cell}=E^0_{cathode}-E^0_{anode}$

$E^0_{cell}=E^0_{[Pb^{2+}/Pb]}-E^0_{[Cu^{2+}/Cu]}$

$E^0_{cell}=-0.13V-(0.34V)=-0.47V$

Now we have to calculate the standard Gibbs free energy.

Formula used :

$\Delta G^o=-nFE^o_{cell}$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant = 96500 C/mole

$E^o$ = standard e.m.f of cell = -0.47 V

Now put all the given values in this formula, we get the Gibbs free energy.

$\Delta G^o=-(2\times 96500\times (-0.47))=+90710J/mole=+90.71kJ/mole\approx +91kJ/mole$

Therefore, the standard Gibbs free energy is +91 kJ/mole

6 0

2 years ago

Which equation describes a reduction?

ira [324]

The answer choice is going to be B.

7 0

3 years ago

Write 0.00000009345 in Engineering Notation with 3 significant figures

melisa1 [442]

Answer:

$93.43\times 10^{-9}$

Explanation:

Scientific notation is the way of writing numbers which are either large or small. The number is written in the scientific notation when the number is between 1 and 10 and then multiplied by the power of 10. Engineering notation is the same version of the scientific notation but the number can be between 1 and 1000 and in this exponent of the ten is divisible by three.

For example, $1000^2$ is to be written as $10^6$ in engineering notation.

The given number:

0.00000009345 can be written as $93.425\times 10^{-9}$

Answer upto 4 significant digits = $93.43\times 10^{-9}$

6 0

2 years ago

A battery changes chemical energy into _____.

Sophie [7]

It turns chemical into electricity

5 0

3 years ago

Read 2 more answers

Look at the bottom of the periodic table. There are two rows of elements separated from the others. Where do these

mina [271]

Answer:

The first row of elements fits in period 6, after the element lanthanum (La). The second row of elements fits in period 7, after the element actinium (Ac). 

I hope this helps!

4 0

3 years ago